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visits member for 3 years, 7 months
seen Oct 17 at 5:14

Jul
2
awarded  Curious
May
15
awarded  Organizer
May
15
revised Question about Binomial Distribution
Changed Title
May
15
suggested suggested edit on Question about Binomial Distribution
Sep
24
accepted How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly?
Sep
24
revised How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly?
added 178 characters in body
Sep
24
comment How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly?
Ahh - my bad! The graph I'd posted is incorrect - the blue graph is $x^x/x!$, whereas it should be ${\log x}^{\log x}/{\log x}!$
Sep
24
comment How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly?
@Alexander: Well, I used the first one, which gave me the aforementioned bound :) i.e ${n \choose k} \leq n^k/k!$
Sep
24
asked How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly?
Jun
6
accepted How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$?
Jun
1
awarded  Commentator
Jun
1
comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$?
Too many good answers - I guess thats a good problem to have :)
Jun
1
comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$?
Btw, could you tell me how to get plots/figures in stackexchange answers - I presume you've a better way than generating it in Matlab/mathematica, exporting it to jpg and uploading it - is there a online graph generator that u use?
Jun
1
comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$?
Well, I'll be... I could swear my Chrome browser at Uni was showing the first brackets around only 3 in the denominator, in your answer - hence I wanted the edit! But, now in FireFox, its showing up correctly, hence I understand why you were confused! Bottomline: your answer is perfectly OK :)
May
31
comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$?
Maybe the formatting of the result is a bit off - it looks like the brackets are around the denominator only, hence the epsilon applies only on it...I don't have edit privileges, perhaps u can fix it? The answer is great otherwise!
May
31
comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$?
@TMM: That's an interesting idea! You can make it into an answer, as it would definitely be one of the answers (and proof strategies) that I was looking for!
May
31
asked How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$?
May
25
awarded  Critic
May
13
awarded  Caucus
May
8
awarded  Informed