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 Dec8 awarded Caucus Jul2 awarded Curious May15 awarded Organizer May15 revised Question about Binomial Distribution Changed Title May15 suggested approved edit on Question about Binomial Distribution Sep24 accepted How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly? Sep24 revised How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly? added 178 characters in body Sep24 comment How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly? Ahh - my bad! The graph I'd posted is incorrect - the blue graph is $x^x/x!$, whereas it should be ${\log x}^{\log x}/{\log x}!$ Sep24 comment How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly? @Alexander: Well, I used the first one, which gave me the aforementioned bound :) i.e ${n \choose k} \leq n^k/k!$ Sep24 asked How do I bound ${{n \log n} \choose {\log n}}\frac{1}{n ^ {\log n}}$ tightly? Jun6 accepted How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$? Jun1 awarded Commentator Jun1 comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$? Too many good answers - I guess thats a good problem to have :) Jun1 comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$? Btw, could you tell me how to get plots/figures in stackexchange answers - I presume you've a better way than generating it in Matlab/mathematica, exporting it to jpg and uploading it - is there a online graph generator that u use? Jun1 comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$? Well, I'll be... I could swear my Chrome browser at Uni was showing the first brackets around only 3 in the denominator, in your answer - hence I wanted the edit! But, now in FireFox, its showing up correctly, hence I understand why you were confused! Bottomline: your answer is perfectly OK :) May31 comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$? Maybe the formatting of the result is a bit off - it looks like the brackets are around the denominator only, hence the epsilon applies only on it...I don't have edit privileges, perhaps u can fix it? The answer is great otherwise! May31 comment How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$? @TMM: That's an interesting idea! You can make it into an answer, as it would definitely be one of the answers (and proof strategies) that I was looking for! May31 asked How to prove/show $1- (\frac{2}{3})^{\epsilon} \geq \frac{\epsilon}{4}$, given $0 \leq \epsilon \leq 1$? May25 awarded Critic May13 awarded Caucus