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 Apr14 comment Possible solutions of a diophantine equation: $p^2+pq+275p+10q=2008$ Ah yes. It's been a while since I've had to make use of a/the trick =) Apr13 comment Possible solutions of a diophantine equation: $p^2+pq+275p+10q=2008$ $(7,2)$?  Mar27 comment Can $y=\frac{e^\frac{t^4}{12}}{e^{\frac{t^3}{3}}}$ be simplified? What a roller-coaster! And @CSil, there's nothing wrong with this answer. You are still left to calculate the difference in the exponent, but now you know the property at work. Mar11 comment Throwing coin 6 times, probability to get H is 1/3. what is the probability to get H in 2 first throws? en.wikipedia.org/wiki/Conditional_probability Mar6 awarded Yearling Mar2 awarded Popular Question Jan29 comment Find the derivative of the question mentioned I got the same result, modulo the order of terms in the numerator/denominator Jan24 comment Can we find the inverse for a vector If you are looking for a multiplicative inverse, you should start thinking about vector multiplication and what the multiplicative identity is (or would be). Jan22 comment Expected value of prime lottery ticket Your expected loss is $8.06 Jan22 answered How to go about solving this inequality question? Jan22 comment How to apply the Chain rule when using standard integrals/differentials? When integrating, it's call u-substitution. Jan22 comment Why is$\frac{\sqrt{x+1}-1}{x}$equal to$\frac{1}{\sqrt{x+1}+1}$? I'd check the domain restrictions, @servabat. Also, note that the second equality follows from the difference of two squares. Jan22 comment how they deduce that$\det A=1$just from the first coeffcient and minor This appears to be a special case that relies on some sort of symmetry in the cofactor expansions along the top ow or left column. But I'm not sure how to explain it concretely. Jan22 revised Is there a rule of integration that corresponds to the quotient rule? rolled back to a previous revision Jan22 comment factor the following expression$25x^2 +5xy -6y^2$Imagine that - someone who actually knows how to teach! Jan22 comment factor the following expression$25x^2 +5xy -6y^2$You found the factor pair of$ac = -150$that sums to$b= 5$. Your comparison is ludicrous, and pedagogy deplorable. Jan22 comment factor the following expression$25x^2 +5xy -6y^2$Yes, but how did you "choose"$15-10$? Why not$9-4$or$1+4$? To a student, your choice just looks like a guess, whence "divine". Jan22 comment factor the following expression$25x^2 +5xy -6y^2$It's not clear to me how you divined that$5 = 15 - 10$(and not some other sum) Jan22 comment factor the following expression$25x^2 +5xy -6y^2$Here's the general method: adamlchan.com/math/topics/ac_factoring/index.php Jan22 comment factor the following expression$25x^2 +5xy -6y^2$@Joffan, that's almost useless. We need to find the factors of$ac = -150\$.