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seen Oct 17 at 23:58

Jun
28
comment Expectation of an event
@Gortaur: it means that you $j_1$ could equal $j_2$, etc.
Jun
28
comment Expectation of an event
This is easy to solve (exactly) with dynamic programming, but I'm not sure how to do it analytically.
Jun
28
revised Sufficient statistic for product of $\Gamma(x + a_i)$
deleted 2 characters in body
Jun
28
revised Sufficient statistic for product of $\Gamma(x + a_i)$
simplified text
Jun
28
comment Sufficient statistic for product of $\Gamma(x + a_i)$
If this question interests you, please help me tag it.
Jun
28
asked Sufficient statistic for product of $\Gamma(x + a_i)$
Jun
17
awarded  Quorum
Dec
29
revised Convolution of probability densities. Having trouble integrating over vector
added 218 characters in body
Dec
28
accepted Convolution of probability densities. Having trouble integrating over vector
Dec
28
comment Convolution of probability densities. Having trouble integrating over vector
thanks! B is the multinomial beta function, which I think normalizes the distribution correctly. the domain of integration is such that the arguments passed to f are always negative (l - x <= l - l = 0).
Dec
26
comment How do you get a Percentage of how far the value is from expected Value
FYI the mean is a synonym for expected value
Dec
25
awarded  Teacher
Dec
25
answered Making Change for a Dollar (and other number partitioning problems)
Dec
25
revised Convolution of probability densities. Having trouble integrating over vector
added 301 characters in body; added 36 characters in body
Dec
25
asked Convolution of probability densities. Having trouble integrating over vector
Dec
17
accepted What is the $d\sigma/\sigma$ rule?
Dec
17
comment What is the $d\sigma/\sigma$ rule?
Thank you very much for this answer. I guess I am a 'true believer.'
Dec
15
asked What is the $d\sigma/\sigma$ rule?
Dec
7
comment Big $\mathcal{O}$ Notation question while estimating $\sum \frac{\log n}{n}$
Can someone repair the title: "Big O notation."
Dec
1
comment $e$ to 50 billion decimal places
@Arturo, I think I understand, thanks.