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seen Jun 2 at 15:46

Hi Im a mathematics student, trying to learn about topics which I am struggling with at school


May
14
awarded  Tumbleweed
May
7
revised Question about Laurent Series expansion
deleted 24 characters in body
May
7
asked Question about Laurent Series expansion
Apr
22
accepted Game Theory and Uniform Distribution question?
Apr
22
comment Please explain uniform distribution to me
thanks but How do you get the length ?
Apr
22
comment Please explain uniform distribution to me
The game theory question deals with the wider theory and why we do certain calculations, this deal with individual calculations and how to do them which calculations to do vs how to do them
Apr
22
asked Please explain uniform distribution to me
Apr
22
revised Game Theory and Uniform Distribution question?
I think you confused b1 with b2 and inequalities wrong way round
Apr
22
suggested suggested edit on Game Theory and Uniform Distribution question?
Apr
22
revised Game Theory and Uniform Distribution question?
added 2 characters in body
Apr
22
comment Game Theory and Uniform Distribution question?
have I incorrectly types the question ? does it not make sense
Apr
22
asked Game Theory and Uniform Distribution question?
Apr
22
awarded  Notable Question
Dec
1
awarded  Popular Question
May
7
accepted Find Laplace Transform of the function
May
7
comment Find Laplace Transform of the function
Are the correct limits $$\hat{f}(s) = \int_0^{\infty} dt \, e^{-s t} + \int_0^{T} dt \, e^{-s t} $$ or mmhenni's post $$ = 2\int_{0}^{T}e^{-st}dt + \int_{T}^{\infty} e^{-st}dt $$
May
7
comment Find Laplace Transform of the function
perhaps its because I have used the limits 0,t and t,infinity as opposed to 0,infinity and 0,t $$ = 2\int_{0}^{T}e^{-st}dt + \int_{T}^{\infty} e^{-st}dt $$
May
7
comment Find Laplace Transform of the function
I get the final answer $$\hat{f}(s) = \frac{2e^{-s T}}{-s}- \frac{1}{-s} -\frac{1}{-s} $$ The denominator will be -s and have to multiply by 2 that went outside the integral
May
6
revised Prove that L[f' ' ](s)$ = $sL[f](s)
edited tags
May
6
accepted Prove that L[f' ' ](s)$ = $sL[f](s)