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Hi Im a mathematics student, trying to learn about topics which I am struggling with at school


Dec
1
awarded  Popular Question
May
7
accepted Find Laplace Transform of the function
May
7
comment Find Laplace Transform of the function
Are the correct limits $$\hat{f}(s) = \int_0^{\infty} dt \, e^{-s t} + \int_0^{T} dt \, e^{-s t} $$ or mmhenni's post $$ = 2\int_{0}^{T}e^{-st}dt + \int_{T}^{\infty} e^{-st}dt $$
May
7
comment Find Laplace Transform of the function
perhaps its because I have used the limits 0,t and t,infinity as opposed to 0,infinity and 0,t $$ = 2\int_{0}^{T}e^{-st}dt + \int_{T}^{\infty} e^{-st}dt $$
May
7
comment Find Laplace Transform of the function
I get the final answer $$\hat{f}(s) = \frac{2e^{-s T}}{-s}- \frac{1}{-s} -\frac{1}{-s} $$ The denominator will be -s and have to multiply by 2 that went outside the integral
May
6
revised Prove that L[f' ' ](s)$ = $sL[f](s)
edited tags
May
6
accepted Prove that L[f' ' ](s)$ = $sL[f](s)
May
6
comment Prove that L[f' ' ](s)$ = $sL[f](s)
thanks, do you know of any online resource that deals with this type of question ?
May
6
awarded  Editor
May
6
comment Prove that L[f' ' ](s)$ = $sL[f](s)
it looks like the laplace transform differentiated
May
6
revised Prove that L[f' ' ](s)$ = $sL[f](s)
deleted 62 characters in body
May
6
comment Prove that L[f' ' ](s)$ = $sL[f](s)
$f(s)= $ $L(ft)(s)$ $$ \int^inf_0 dx $
May
6
comment Prove that L[f' ' ](s)$ = $sL[f](s)
what would be my u and v values, if I applied the integration by parts method
May
6
asked Prove that L[f' ' ](s)$ = $sL[f](s)
May
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awarded  Supporter
May
6
comment Using Convolution Theorem to find the Laplace transform
do I need to evaluate $$\hat{h_{S*T}}(p) = \left ( \frac{2 - e^{-p S}}{p} \right )\left ( \frac{2 - e^{-p T}}{p} \right )$$ between 0 and t ? in my workbook we would replace the first t with (t-x) and the 2nd t with x . that does not apply in this case
May
6
accepted Using Convolution Theorem to find the Laplace transform
May
6
comment Find Laplace Transform of the function
Hi, could you please also answer this question math.stackexchange.com/questions/382613/…
May
6
comment Using Convolution Theorem to find the Laplace transform
so essentially what $$ \int^t_0 du f_T(t-u)f_s (u), t>0 $$ means is to find the Laplace transform using convolution We find the laplace transform using the previous method and then we multiply the laplace transform by itself but replacing t by s for the first function ?
May
5
asked Using Convolution Theorem to find the Laplace transform