Jules
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 Sep 16 awarded Commentator Sep 16 comment Under which conditions do positive real roots exist in a quadratic of two variables? I know how to answer the question for a quadratic in one variable, so I have tried to reduce this problem to that problem, but so far unsuccessfully. Sep 16 asked Under which conditions do positive real roots exist in a quadratic of two variables? May 5 comment Matrix Calculus and Matrix Derivatives You're not wrong, but this does not contradict my previous statement. If you use the same basis for the domain and range the 4x4 matrix would look like the identity matrix you expect. May 5 comment Matrix Calculus and Matrix Derivatives Yes, the basis of the domain and the range are permuted. May 5 comment Matrix Calculus and Matrix Derivatives This is the identity matrix in disguise, the indices are just permuted. May 4 awarded Teacher May 4 revised Matrix Calculus and Matrix Derivatives added 59 characters in body May 4 answered Matrix Calculus and Matrix Derivatives Mar 8 comment Understanding the integral of $x^a$ In Taylor series and Laurent series we think of $x^0 = 1$. I wonder if there is an alternative series expansion which uses the logarithm for the 0th power. If I remember correctly there is a problem with the logarithm in conventional complex analysis, because the singularity at 0 is a strange kind of singularity. Or maybe I'm talking nonsense... Mar 8 accepted Understanding the integral of $x^a$ Mar 8 comment Understanding the integral of $x^a$ I'll ask a follow-up question if you don't mind. I hope it is not too vague. Does this mean that in some sense the logarithm ought to belong to some extension of the set of polynomials with integer exponents, where the logarithm is related to $x^0$? Mar 8 comment Understanding the integral of $x^a$ Thanks, that does help, but it does not completely resolve my confusion. I feel like there is something going on with the order of the limits, because if you have the limit of $3^a/a$ as $a$ goes to 0 then it's not $\log 3$. What am I missing? edit: oh, I already see my mistake, thanks! I was confused because I only looked at the indefinite integral. Mar 8 asked Understanding the integral of $x^a$ Nov 9 awarded Editor Nov 9 revised Why is Newton's method faster than gradient descent? edited title Nov 9 asked Why is Newton's method faster than gradient descent? May 7 awarded Scholar May 7 comment Numerical optimization with nonlinear equality constraints Thanks, that's exactly what I was looking for! May 7 accepted Numerical optimization with nonlinear equality constraints