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seen Jun 6 at 3:59

Apr
21
awarded  Yearling
Mar
22
comment How to show $(s+t)^p\le 2^{p-1}(s^p + t^p)$ for $p\gt1$
I guess you also require s,t greater or equal to zero. Then from Jensen's inequality, the mean of the p power is greater or equal to the p power of the mean.
Mar
7
answered Trying to triangulate from two (or three) known points.
Jan
19
comment Find a polynomial whose splitting field is $\mathbb{Q}[\alpha,i]$
If it were reducible, there would be a linear factor, and plus or minus one would be a root.
Jan
18
comment Field extension of complex root of cubic equation
If the splitting field contains complex elements, then taking the complex conjugate is an isomorphism, of order two, which must be a subgroup of the full Galois group. So the order of the Galois group must be even.
Jan
18
comment Field extension of complex root of cubic equation
If you want to adjoin one root, then they are all algebraicaly equivalent. There is no advantage to choosing a complex root. The order of the reaulting field will be three. So, do you see the problem here?
Jan
18
comment Limit of Sequence n/(n+1)
It's also getting closer to 1000.
Jan
18
comment Maximum area under a curve by calculus of variations
OK, but the curve is not generally a semicircle. The curve is a circle, with the given line segment a chord, not necessarily a diameter.
Jan
17
answered Maximum area under a curve by calculus of variations
Jan
11
revised Prove $e^x, e^{2x}…, e^{nx}$ is linear independent on the vector space of $\mathbb{R} \to \mathbb{R}$
Correction
Jan
10
answered Prove $e^x, e^{2x}…, e^{nx}$ is linear independent on the vector space of $\mathbb{R} \to \mathbb{R}$
Jan
4
awarded  Nice Answer
Jan
4
answered Geometric Proof that $\mathbb{Z}[\sqrt{-3}]$ is non-Euclidean
Jan
1
answered Let $G$ be a finite abelian group of odd order. Which of the following define an automorphism of $G$?
Dec
27
comment Find five consecutive odd integers such that their sum is $55$.
It's simpler to let the third number be n.
Dec
17
answered Simple inequality true?
Dec
13
comment Very tricky probability
Consider the probability that both selected balls are yellow.
Dec
10
comment a question about Lagrange multiplier?
The easiest way is to use Jensen's inequality, noting how the convexity changes for different values of k. Consider positive and negative values, greater and less than one.
Dec
9
comment Group with $a=a^{-1}$ for all $a\in G$ is abelian
The commutator is 1.
Dec
8
revised Area of Parallelogram in an Ellipse
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