kevmo314
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 Oct 12 awarded Popular Question Oct 10 awarded Commentator Oct 10 comment Ants moving on a grid Ah, I got ~82 turns. I verified this was correct with someone else who wrote the simulation as well. I don't want to share my code since this is an interview question, but someone posted theirs on a similar question here: gist.github.com/dhalik/51a5c0dc621a43d3bb94 Oct 10 comment Ants moving on a grid @Tad how would you invert that matrix in a reasonable amount of time? An O(n^3) algorithm would be rather slow. I could see maybe doing it via Cholesky factorization though? Oct 10 comment Ants moving on a grid Yes, the solution via simulation is trivial, but not what I'm interested in. Oct 7 asked Ants moving on a grid Jul 20 awarded Critic Sep 7 awarded Autobiographer Jun 21 comment Limit of a summation Ah I wish I could accept multiple answers. Both of your answers were incredibly helpful. Thanks so much! Jun 21 accepted Limit of a summation Jun 21 comment Limit of a summation Ah, that explanation makes sense. Thank you very much. Jun 21 comment Limit of a summation Though I clearly specify that $x\to\infty$. Wouldn't WolframAlpha put out some message before making that assumption? Jun 21 comment Limit of a summation Yes, added it to the original post if this link doesn't work: wolframalpha.com/input/… Jun 21 revised Limit of a summation added 172 characters in body Jun 21 comment Limit of a summation But how does this explain what WolframAlpha is doing? Is it making a mistake? Jun 21 asked Limit of a summation Mar 23 awarded Editor Mar 17 comment Proof of Heine-Borel in $\mathbb R^n$ The first part of this proof seems to make sense and I understand that part of the construction of a finite subcovering, but I'm not sure what happens after "We strip off all the elements..." Is that necessary for the proof itself as didn't it just construct a finite subcovering? If so, could you explain that a little more? Mar 17 accepted Proof of Heine-Borel in $\mathbb R^n$ Mar 17 comment Proof of Heine-Borel in $\mathbb R^n$ Finite covers, but we know that sequentially compact <=> compact for metric spaces.