Beni Bogosel
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 Apr 22 comment Weird subfields of $\Bbb{R}$ @temo The question is quite old, so I don't really remember. I guess it was in some book on linear algebra or on some other topics in real analysis Apr 11 comment I've found a MATLAB plot in a book and want to know which command the authors used for the plot If you need to swap axes just change the role of X and Y and transpose ut: surf(Y,X,ut') Apr 11 comment I've found a MATLAB plot in a book and want to know which command the authors used for the plot If the graph is entirely black, then your ut contains only one value. Probably there may be a mistake in the computation of ut. Apr 11 comment Computing a matrix from its exponential Is your matrix diagonalizable? Do you know $e^{tA}$ or just $e^A$? Apr 10 comment I've found a MATLAB plot in a book and want to know which command the authors used for the plot I guess that since you're reading the book (which is about Matlab applications) you must learn how to do it from it... Anyway, there's no command which plots you the solution right away. You need to construct a script which does it... Continue reading the book (by the way, you could mention its title... if you want someone to help). The code might be presented somewhere Feb 28 comment $f(x)$ decreasing and positive implies $f'(x)$ converges to 0? Is your limit point $\infty$? If so, then if $f(x)$ does not converge to zero what makes you think that $xf(x)$ can converge to zero? Dec 10 comment Cutesy Applications of Fermat's Last Theorem (or others) From the other part of the product $(a^n-b^n)^2+(b^n+c^n)^2+(a^n+c^n)^2 = 0$. Dec 10 comment Cutesy Applications of Fermat's Last Theorem (or others) One of the factors given by the equation is $a^n+b^n-c^n$ which by FLT is never zero. Nov 17 comment Proving that a Finite Field Over Its Prime Field Is Galois I don't remember making this review. Galois theory is not among my favorite subjects neither... Maybe your answer got mixed up with something because it is too short, like a comment. Nov 15 comment Minimizing $\int_{0}^{1} (1+x^2)f(x)^2 dx$ for $f(f(x)) = x^2$ @mick: No one's voting to close because a source is missing, but the fact that you are the source and you don't know the solution is not very encouraging. I asked since some problems taken from high profile contests or exercices from advanced books are not easily solved if you don't have some context. Furthermore, if you just made up the problem, it may not even be possible to solve it... Nov 15 comment Minimizing $\int_{0}^{1} (1+x^2)f(x)^2 dx$ for $f(f(x)) = x^2$ What's the source of this problem? Nov 15 comment Minimizing $\int_{0}^{1} (1+x^2)f(x)^2 dx$ for $f(f(x)) = x^2$ @AlfredYerger: I think $f^2$ means $f$ squared. If the superscript refers to composition like you say, then you just replace by $f\circ f$ by $x^2$ and you don't have anything to optimize. Nov 15 comment How can you plot straight lines in Matlab using only values on x axis and the gradient of each line? If you want any real help with your Matlab code you'd better write the whole code properly and then ask exactly what you need. You do not explain the mathematical problem and it is not really clear what you want the matlab program to do. Nov 14 comment Proving that a Finite Field Over Its Prime Field Is Galois This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review Nov 12 comment Polynomial with complex coefficients proof problem The only case where a polynomial has infinitely many roots is where the polynomial is equal to zero everywhere. Then every number is a root. If a polynomial is not constant zero then it has finitely many roots. Nov 12 comment Polynomial with complex coefficients proof problem It doesn't matter if a polynomial has complex or real coefficients. The idea is that it can only have a finite number of roots. Thus, this is a useful fact that you can learn about polynomials: if a polynomial has infinitely many roots then it is the zero polynomial. Nov 8 comment An isosceles trapezium @kissanpentu: $E$ is the midpoint of $AP$ and the triangle $APQ$ is rectangle. This means that the triangle $EPQ$ is isosceles and the angles $EPQ$ and $EQP$ are equal. Since the angle $FQP$ is half the angle $APQ$ by hypothesis, it follows that it is also half the angle $EQP$ and thus $QF$ is the bisector of this angle. Nov 6 comment Continuity of line integral as a function of path @matb: Have you read my comment? If you only consider uniform convergence of the paths, the integrals are not continuous. For $f \equiv 1$, for example you only have lower semicontinuity, You should consider convergence in the $C^1$ norm if you want continuity. Nov 5 comment Continuity of line integral as a function of path The term $|\gamma'(s)|$ is not necessarily uniformly bounded. Take a sequence of high oscillating curves converging to $\gamma$. I guess this already gives you a counter example: Take $f \equiv 1$ so that you are, in fact dealing with the length of curves. It is known that length of curves is lower semicontinuous, but it is not necessarily continuous. Again, high oscillating curves may converge uniformly to a curve while having lengths which are much higher than the length of the limit curve. Oct 23 comment Ask an optimization problem Did you compute the optimality conditions? You intend to do numerical computations?