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Oct
21
comment Nonlinear equation in two unknowns with unique solution over the field of complex numbers
May I ask why are you voting to close the question? Is the answer trivial? What is it then?
Oct
21
comment Nonlinear equation in two unknowns with unique solution over the field of complex numbers
I have edited the question to state the allowed range of functions.
Oct
21
revised Nonlinear equation in two unknowns with unique solution over the field of complex numbers
deleted 25 characters in body
Oct
21
comment Nonlinear equation in two unknowns with unique solution over the field of complex numbers
I have edited the question to avoid confusion.
Oct
21
comment Nonlinear equation in two unknowns with unique solution over the field of complex numbers
@GerryMyerson Please don't restrict the functions to only polynomials.
Oct
21
comment Nonlinear equation in two unknowns with unique solution over the field of complex numbers
@Mathmo123 I am thinking about the so called elementary functions. en.wikipedia.org/wiki/Elementary_function
Oct
21
revised Nonlinear equation in two unknowns with unique solution over the field of complex numbers
deleted 25 characters in body
Oct
21
comment Nonlinear equation in two unknowns with unique solution over the field of complex numbers
I am not asking about the equation $a^2+b^2=0$. I am asking whether there exists a nonlinear equation in two unknowns which has a unique solution over the field of complex numbers. Sorry for the confusion.
Oct
21
asked Nonlinear equation in two unknowns with unique solution over the field of complex numbers
Jul
2
awarded  Curious
Jun
6
accepted Basic question about wedge product
May
11
awarded  Popular Question
Apr
30
comment Regarding usage of $\pm$ sign
@TuckerRapu These are completely different questions, and have completely different answers.
Feb
13
awarded  Popular Question
Dec
4
comment Proving that matrix is positive definite
I think that in your answer "if and only if all $a_i$ are non-zero" should be changed to "if and only if not all $a_i$ are zero".
Dec
3
comment Question about continuous differentiability
Thank you. This helped me to understand as well: freemathhelp.com/forum/threads/…
Dec
3
accepted Question about continuous differentiability
Dec
3
comment Question about continuous differentiability
So, can we say that $f(x,y)$ is continuously differentiable with respect to $x$?
Dec
2
revised Question about continuous differentiability
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Dec
2
comment Question about continuous differentiability
@user99680 In the numerator you have the term $1+\frac{y^2}{\sqrt{x^2+y^2}}$. If you substitute x and y by zeros, u get $1 + \frac{0}{0}$ which is undefined.