Anush
Reputation
Top tag
Next privilege 75 Rep.
Set bounties
 Mar27 awarded Popular Question Dec14 comment Estimating the mode @alex.jordan Sampling without replacement would make the question rather easy as you say. I don't have a fixed idea for how to estimate the mode's frequency given the sample but I was thinking that you could maybe look at the frequency of the mode of the sample and try to adjust that for the sample size you have taken. Dec14 asked Estimating the mode Sep6 comment Expected time to get from bottom left to top right in a square Can you give any intuition for why it might be much quicker to get to the opposite corner than to some point in the middle of the side? This isn't obvious to me. Jul17 revised Entropy of matrix vector product added 122 characters in body; edited tags Jul17 awarded Curious Jul16 revised Entropy of matrix vector product added 25 characters in body Jul16 revised Entropy of matrix vector product added 10 characters in body Jul16 comment Entropy of matrix vector product @robjohn Does the edit make it clearer? Jul16 revised Entropy of matrix vector product added 279 characters in body Jul15 revised Entropy of matrix vector product added 43 characters in body Jul15 revised Entropy of matrix vector product edited tags Jul15 asked Entropy of matrix vector product May13 revised Why are two statements about a polynomial equivalent? fixed brackets and fractions May13 suggested approved edit on Why are two statements about a polynomial equivalent? May13 comment Which vectors can give zero inner products forever I expect this is obvious to an expert, but does this answer mean there are vectors $v$ other than the ones the OP listed or not? Apr21 awarded Nice Question Apr3 comment Are the entries in matrix/vector product independent Yes but your argument makes no reference to that. It would seem to apply equally to the $0,1$ case. What is it about $\pm 1$ that is making the difference? Apr3 comment Are the entries in matrix/vector product independent Not so fast! If the vector $v$ had values which were $0$ or $1$ the $y_i$ would not be independent. If you knew, for example that the first half of the $y_i$'s were $0$ it would be a good guess the next half has plenty of $0$s in it too. Feb13 comment Smallest non-zero eigenvalue of a (0,1) matrix Cross-posted to mathoverflow.net/questions/157472/… now.