sir_thursday
Reputation
Top tag
Next privilege 250 Rep.
 Mar 14 comment Expected value of Stock Price, Poisson Process Why do you have that $E[S_{t}^{2}] = E[S_{0}^{2}(\sigma^{2} + \mu^{2})^{N(t)}$ and not $E[S_{t}^{2}] = E[(S_{0}\mu^{N(t)})^{2}] = E[(S_{0}^{2}\mu^{2N(t)})]$? Mar 14 awarded Excavator Mar 14 revised Expected value of Stock Price, Poisson Process Fixed latex error Mar 14 suggested approved edit on Expected value of Stock Price, Poisson Process Feb 8 comment Proof of the existence of a reversible stationary distribution @Did What exactly are you trying to say with the above equality? Jan 29 accepted Prove the following simple exponentiation equality. Jan 29 comment Prove the following simple exponentiation equality. ^ Makes sense. Thanks Chaz Jan 29 comment Prove the following simple exponentiation equality. You mean the taylor series representation for the log? Jan 29 asked Prove the following simple exponentiation equality. Oct 24 accepted Jordan normal form and invertible matrix of generalized eigenvectors proof Oct 24 comment Jordan normal form and invertible matrix of generalized eigenvectors proof Thanks for covering both cases. Just as a note, the Jordan normal form I meant in the problem was case 2, sorry I didn't specify. Either way, again, thank you! Oct 24 asked Jordan normal form and invertible matrix of generalized eigenvectors proof Nov 3 awarded Critic Nov 3 awarded Citizen Patrol Sep 27 comment Taking the log of both sides to determine big Theta/Omega/O Oh okay, so when showing that $2^{n^2} \notin O(2^n)$ through contradiction, we can't do something like: $2^{n^2} \leq c \times 2^n$ and take the log of both sides to get $n^2 \leq \log(c) + n$ and so forth... Sep 27 accepted Taking the log of both sides to determine big Theta/Omega/O Sep 27 comment Taking the log of both sides to determine big Theta/Omega/O So $\log(f(n)) \leq c\log(g(n)) \rightarrow f(n) \in O(g(n)^c)$? Sep 27 comment Taking the log of both sides to determine big Theta/Omega/O How can $\log(f(n)) \in O(\log(g(n)) \rightarrow f(n) \in O(g(cn))$? It's false that $\log(n^2) \in O(\log(n)) \rightarrow n^2 \in O(cn)$ Thanks for helping Sep 27 revised Taking the log of both sides to determine big Theta/Omega/O added 5 characters in body Sep 27 asked Taking the log of both sides to determine big Theta/Omega/O