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7h
answered Population standard deviation or sample standard deviation
1d
comment Normal vector in curvilinear coordinates
@Jay, fantastic! Glad I was able to help.
1d
comment Normal vector in curvilinear coordinates
Changing coordinates doesn't change the manifold. Coordinates are just different charts describing the same manifold. Have you calculated the helix to have no curvature in cylindrical coordinates?
1d
answered Complex analysis textbook advise
1d
answered Normal vector in curvilinear coordinates
2d
revised Lagrange Multiplier Method On Linear Equation Set
added 7 characters in body
2d
answered Lagrange Multiplier Method On Linear Equation Set
2d
comment Cylindrically symmetric vector field
I'm looking at the exercises for ch 4 and I don't see this identity in there.
2d
comment Cylindrically symmetric vector field
Where in Zangwill? Can you give me a chapter or section number?
2d
comment Cylindrically symmetric vector field
@LunaSage, this is consistent with the definition of cylindrical symmetry you provided. Are you sure that is the one you should be using?
2d
comment Cylindrically symmetric vector field
Why do you think this should be true?
2d
revised Polynomial of degree $2$ has at most $2$ roots
added 5 characters in body
2d
answered Polynomial of degree $2$ has at most $2$ roots
2d
answered Proving a differential equation is a circle
2d
comment Integrals on the real line using contour integration
I think you are missing a factor of $z$ in the numerator of the integrand.
2d
comment Integrals on the real line using contour integration
The roots of $x^2+4$ are $2i$ and $-2i$. Where are you getting $i\sqrt{2}$ from?
2d
answered Easy question : $\int (xdy+ydx)$
2d
reviewed Approve Laplace transformations for dummies
2d
comment Can a matrix be similar to more than one matrix?
@Omnomnomnom, fair enough. Good answer btw, nice and simple.
2d
comment How to prove that $f_n(x)=\frac{nx}{1+n\sin(x)}$ does not converge uniformly on $[0, \pi/2]$?
@S.Panja-1729, in your second line you wrote "When $x\neq 0$ then $f(x)=1$." This still needs to be fixed.