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Oct
10
comment Fast bijective $\mathbb{Z} \times \mathbb{Z} \rightarrow \mathbb{Z}$
This is an interesting approach, I hadn't thought of it. Its very straight forward to implement, and should be fairly fast. Though is there not a more 'elegant' approach? By this I mean without intermediary transformations, to make the single question a series of simpler questions.
Oct
10
comment Fast bijective $\mathbb{Z} \times \mathbb{Z} \rightarrow \mathbb{Z}$
What would the function look like to have it spiral like that?
Oct
10
awarded  Editor
Oct
10
revised Fast bijective $\mathbb{Z} \times \mathbb{Z} \rightarrow \mathbb{Z}$
added 76 characters in body
Oct
10
awarded  Student
Oct
10
asked Fast bijective $\mathbb{Z} \times \mathbb{Z} \rightarrow \mathbb{Z}$
Aug
23
awarded  Informed
Mar
31
awarded  Autobiographer