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 Nov13 accepted How to derive the equation for a bézier curve Nov12 awarded Notable Question Nov12 awarded Popular Question Sep23 comment Help with a probability problem @Sudarsan Oh yes, I see the difference. Sep23 comment Help with a probability problem Oh, this is just brilliant, but I'm afraid this way of thinking is way too elegant and advanced for me! I can just marvel at your logic. Thanks! Sep23 accepted Help with a probability problem Sep23 comment Help with a probability problem @Sudarsan Oh, thanks! I used $\Pr(H_{1...10})$ because it's same for all of the ten hypotheses: $\frac{1}{10}$, but it does look neater with your notation! Thanks :-) Sep23 asked Help with a probability problem Jun30 revised How to derive the equation for a bézier curve Updated with more information Jun30 awarded Commentator Jun30 comment How to derive the equation for a bézier curve Oh, this actually demystifies Bézier curves a little, but I still don't understandâ€”I am not sure what I don't understand. sigh Jun30 revised How to derive the equation for a bézier curve fixed weird wording Jun30 asked How to derive the equation for a bézier curve Sep15 accepted Solving $7 = 8 - 2e^{-3k}$ Sep15 comment Solving $7 = 8 - 2e^{-3k}$ Oh, we were getting that answer, too. I guess she copied down the wrong solution or something. Haha. Thanks! Sep15 asked Solving $7 = 8 - 2e^{-3k}$ Jun5 comment Questions about Lines and Circles. Lots of them! Uh, it looks a little broken, but I think it's readable :x Sorry about that. Jun5 comment Questions about Lines and Circles. Lots of them! Okay, I understand most of what you've said, I'm just confused about one thing. Is the following correct?: $Ax-By-C=0\Leftrightarrow y=\frac{A}{B}x-\frac{C}{B}\Leftrightarrow \frac{x}{C}+\frac{y}{-C/B}=1.$ I am assuming I got it wrong... Jun5 awarded Supporter Jun5 comment Questions about Lines and Circles. Lots of them! Oh God. Wow, you're a genius! Side note: I don't know how to calculate a slope. D: [Frankly, I've been calling it ~direction~ this whole time. Well, I'm not English, so I suppose it's an understandable mistake.] Thanks so much