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6h
answered Do we write a metric tensor as a matrix?
Jan
16
revised Taylor series for $\sqrt{x}$?
added 6 characters in body
Jan
16
comment Proving by induction that any two natural numbers are equal.
Doesn't change anything, what is important is that $\mathbb N$ has a minimal element.
Jan
16
revised Proving by induction that any two natural numbers are equal.
deleted 39 characters in body
Jan
16
comment Proving by induction that any two natural numbers are equal.
Sorry, haven't read this...made an edit.
Jan
16
revised Proving by induction that any two natural numbers are equal.
deleted 311 characters in body
Jan
16
answered Taylor series for $\sqrt{x}$?
Jan
16
answered Proving by induction that any two natural numbers are equal.
Jan
13
answered $R$ local ring, $I$ maximal ideal then $x\notin I$ implies $x$ unit
Jan
12
comment Can it be proven rigorously?
Nope, $S:= \{ v > 0 | v \leq \epsilon \text{ for all } \epsilon >0 \} $ has nothing to do with any epsilon. There is nothing circular here.
Jan
12
answered Can it be proven rigorously?
Jan
12
answered $f(x) = x$ or a , if $f(x)$ and $a$ is known find $x$ boolean algebra
Jan
9
comment $f(x) = x$ or a , if $f(x)$ and $a$ is known find $x$ boolean algebra
Think about sets: if $Y=X\cap A$ or $Y=X \cup A$, then there are many solutions for $X$ given $A$ and $Y$
Jan
7
answered Proving the remainder when a polynomial is divided by an integer.
Dec
19
answered Is Relativity a specific instance of Riemannian geometry?
Dec
19
answered Prove that $\mathbb{Z}$ and $\mathbb{Q}$ are not isomorphic as groups
Dec
18
comment How to visualize $f(x) = (-2)^x$
tell your students that a function $f(x)=a^x$ is given only if $a>0$, don't even define $(-2)^{m \over n}$ - it would be an exercise to ask students whether this expressions makes sense and what the result should be.
Dec
18
comment Does this definition of “limit point” really work
A reason might be, that Tapps definition is easier to understand, and what he wants is a criterion for a closed subset (contains all limit points?) and maybe this works in his context.
Dec
18
comment What is a Simple Group?
(2) Well $|G|>2$ because if $|G|=1$ then there is nothing to do and $|G|\neq 2$ is given. (3) There cannot be an injection of a set with more than two elements into a set with two elements.
Dec
17
comment What is a Simple Group?
Your points (5) and (6) are rather simple: if the kernel is $\{1\}\neq G$ then $G\rightarrow G'/N$ is injective and $|G|>2$