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seen Nov 14 at 19:14

May
29
comment intuition for the closed form of the fibonacci sequence
Damn, well explained.
May
29
comment intuition for the closed form of the fibonacci sequence
@BrianM.Scott I think so. Let me work it out and see, thanks!
May
29
comment intuition for the closed form of the fibonacci sequence
Cool! Sounds like I'll understand this better by figuring out how to find closed form solutions for recurrences. "The sqrt(5) in the Binet formula ultimately comes from the initial conditions F0=0 and F1=1" could you elaborate more on this?
May
29
comment intuition for the closed form of the fibonacci sequence
Yes. Okay, so that clears up my first question. The next question: why divide by sqrt(5)?
Feb
8
comment Calculating the “jaggedness” of a distribution
Why would it be bigger for distribution #2? AFAIU, it would probably be smaller than #2 after normalizing, because #1 would be a vector like [.25 .25 .2 .3] and #2 would be something like [.1 .3 .1 .3].