Denis
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 Mar11 awarded Yearling Feb22 awarded Nice Answer Feb17 comment What is a limit point @TSJ lmgtfy.com/?q=limit+point I believe in your previous remark you had "accumulation points" in mind, i.e. point that are not isolated. Feb16 comment What is a limit point @TSJ Yes they are, they are limits of constant sequences from $S$... Jan26 answered Multiplication of rational with irrational number? Jan22 revised Set Theory: Cardinality of functions on a set have higher cardinality than the set deleted 8 characters in body Jan22 comment Does $A\times A\cong B\times B$ imply $A\cong B$? Why isnt' it enough to project onto the first component to get $A\cong B$ Jan22 answered Set Theory: Cardinality of functions on a set have higher cardinality than the set Jan20 revised Linear space and cardinals remark on S infinite Jan20 comment Linear space and cardinals yes this is only for infinite $S$, I'll add it Jan20 revised Linear space and cardinals typo Jan20 comment Linear space and cardinals I edited the answer to make it rigorous. Jan20 revised Linear space and cardinals added 569 characters in body Jan20 comment Linear space and cardinals Then just take the upper bound in the class of cardinals, which is the smallest cardinal bigger than all elements in your set, the proof still goes through. Jan20 comment Find Disconnect Graph with Degree Sequence disconnected means that your graph is cut into several "potatoes" (at least $2$) with no edge between each other. "Connected component" is the name for "potato". If a potato is of size at least $8$, and the total number of vertices is $11$, this means at most $3$ vertices are left for other potatoes. Jan20 comment Linear space and cardinals Indeed, you need to know that the class of cardinals is totally ordered, which requires axiom of choice. Once you know this, just look at all the cardinals of independent subsets, and take the maximal (it is bounded by the cardinal of the whole vector space so you have an upper bound, the maximal always exists). Jan20 answered Show this language structure models this sentence. Jan20 comment Linear space and cardinals then just replace "dimension" by "maximum cardinal of independent subset" in the proof... Jan20 comment Linear space and cardinals you mean you want a proof that does not use the notion of dimension ? Jan20 answered Find Disconnect Graph with Degree Sequence