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seen Mar 20 at 2:04

Mar
19
asked Hellinger Integral properties
Mar
19
comment Absolutely Continuous measures and Hellinger integral
@JasonJones Good point. That was really obvious...oops. Thanks! Any ideas on the other question?
Mar
19
asked Absolutely Continuous measures and Hellinger integral
Mar
10
awarded  Yearling
Mar
3
comment Proving an operator $D: L^2[0,1]\rightarrow C'$, $Df(t)=\int^t_0 f(s) ds$ is unitary
I forgot to use the $L^2[0,1]$ inner product for $\langle f,g \rangle$. Thanks. If I was evaluating $\langle Df,g \rangle$, which inner product would I use? I want to find $D^*$ the adjoint which should be just $D^-1$ since D is unitary but I want to double check that makes sense.
Mar
3
accepted Proving an operator $D: L^2[0,1]\rightarrow C'$, $Df(t)=\int^t_0 f(s) ds$ is unitary
Mar
3
asked Proving an operator $D: L^2[0,1]\rightarrow C'$, $Df(t)=\int^t_0 f(s) ds$ is unitary
Mar
3
revised Abstract Wiener space and integration related to a trace class operator
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Mar
3
asked Abstract Wiener space and integration related to a trace class operator
Mar
3
accepted Borel measures on $\mathbb{R}$ questions
Feb
11
revised Operators on a Hilbert space question
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Feb
11
asked Operators on a Hilbert space question
Feb
11
asked Borel measures on $\mathbb{R}$ questions
Jan
30
accepted The trace class operators are the dual of the compact operators
Jan
28
comment The trace class operators are the dual of the compact operators
@Norbert see above
Jan
28
revised The trace class operators are the dual of the compact operators
added 93 characters in body
Jan
28
asked The trace class operators are the dual of the compact operators
Jan
28
accepted The Trace Class Operators Form a Banach Space
Jan
28
awarded  Popular Question
Jan
25
comment The Trace Class Operators Form a Banach Space
Could you explain why the map you provide is an isometry? I looked at that book and couldn't quite follow as it was on a higher level than I am.