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Aug
17
accepted Condition for existence of a continuous function
Aug
17
accepted double integral.
Aug
17
accepted What's Geometry?
Aug
16
comment Dimension definition
Thank you so much
Aug
16
comment Dimension definition
Thank you so much, very clear. I accepted you answer, but can I accept more than one answer? . I am not so knowledgeable about this.
Aug
16
accepted Dimension definition
Aug
16
revised Dimension definition
added 23 characters in body; added 13 characters in body
Aug
16
asked Dimension definition
Aug
14
comment Divergence theorem to prove a relation.
@Sepideh, I understand your point, I am just trying to see how to make this work, what changes to make, if its possible to make a similar conclusion for a scaler function.
Aug
14
comment Divergence theorem to prove a relation.
Sepideh, I agree with what you said. What I am trying to say, if I use the divergence theorm on $F(x,y,z)=f(x)(c_1,c_2,c_3), \ \ where \ c_i \ are \ constants$ Now apply the divergence theorm $\iint \limits _S cf (r). \ \Bbb dS = \iiint \limits _B( c.\bigtriangledown f + f \ (\bigtriangledown c))\ \Bbb dV$ second term on right hand side will vanish. then I did not carry out the calculation, as I am not sure if it will yield anything similar.
Aug
14
comment Divergence theorem to prove a relation.
Would the same result hold if $f$ is scaler, and multiply by constant vector.?
Aug
14
comment Divergence theorem to prove a relation.
Thanks Alex, your notations corrections makes the problem obvious.
Aug
14
accepted Divergence theorem to prove a relation.
Aug
14
awarded  Commentator
Aug
14
comment Divergence theorem to prove a relation.
Yes, I multiply f with constant vector
Aug
14
revised Divergence theorem to prove a relation.
added 48 characters in body
Aug
14
asked Divergence theorem to prove a relation.
Aug
14
comment Proof of the irrationality of $\sqrt n$, where $n$ is square free
As I said, I am just reviewing things here.
Aug
14
comment Proof of the irrationality of $\sqrt n$, where $n$ is square free
Thanks to all of you. I am trying to use conductor ideal of the ring $Z$, to prove this in general. I just want to see how things work, basicly I am all motivated by the proof that if $ \sqrt 2 \in Q$ and define $ A=[{n| \ \ \ n\sqrt2 \in N}]$ and from there continue with the classical argument that this has min...etc. so I wanna see what Algebra hidden in there.
Aug
14
revised Proof of the irrationality of $\sqrt n$, where $n$ is square free
added 33 characters in body