| bio | website | |
|---|---|---|
| location | Tennessee | |
| age | 19 | |
| visits | member for | 2 years, 3 months |
| seen | 58 mins ago | |
| stats | profile views | 32 |
I am an undergraduate university student double majoring in Computer Science and Mathematics hoping to pursue a research career in cryptography. Other interests include software engineering and Linux-based system administration.
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Jan 17 |
awarded | Commentator |
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Jan 17 |
comment |
Can you provide me historical examples of pure mathematics becoming “useful”? @N.S.: we know integer factorization is in $\mathcal{NP}$ (it's trivial to show), although we're not sure where exactly it fits in $\mathcal{NP}$. The real issue is pinning down exactly which complexity class factorization fits in, as well as proving $\mathcal{P}\ne \mathcal{NP}$. |
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Jan 14 |
comment |
function for $f: [0,\infty) \to (0,1]$? It would be better to use a language's built-in exp function, if it has one (and most do), instead of coding in the Maclaurin series. |
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Dec 25 |
comment |
Why is 'abuse of notation' tolerated? @JoeZeng: some languages capitalize 'You' in order to indicate respect, so I think it may be something along those lines. |
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Oct 27 |
awarded | Editor |
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Oct 27 |
revised |
Is Gödel's theorem invalid? Fix various typos |
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Oct 27 |
suggested | suggested edit on Is Gödel's theorem invalid? |
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May 27 |
awarded | Enthusiast |
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May 17 |
comment |
Algebraic Solution to $\cos(\pi x) + x^2 = 0$ Thanks for the tool. Unfortunately, while the results look promising for the first few digits, even expanding to the next "section" of digits with Wolfram|Alpha ends up with a decimal that's not in that tool's database. |
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May 17 |
accepted | Algebraic Solution to $\cos(\pi x) + x^2 = 0$ |
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May 17 |
asked | Algebraic Solution to $\cos(\pi x) + x^2 = 0$ |
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Feb 2 |
awarded | Yearling |
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Dec 30 |
comment |
Something that I found, and would like to see if it's known. As a layman, the sheer number of patterns that mathematicians have already found and documented amazes me. I suppose math's been around for a long while, but still! |
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Nov 22 |
comment |
Which step in this process allows me to erroneously conclude that $i = 1$ @GEdgar: In my experience with high school (just a year ago for me), almost no properties are given restrictions except when their formal definitions are introduced at the very beginning, then they're never mentioned again. So, while the restrictions placed on a property may be "taught" in high school, that's not a guarantee: $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$ is one that comes to mind almost immediately as having a restriction that's almost never mentioned in a high school class. |
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Jul 25 |
awarded | Critic |
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May 12 |
accepted | Conditions for a function to have guaranteed global extrema along $[a, b]$ |
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May 11 |
comment |
Conditions for a function to have guaranteed global extrema along $[a, b]$ @Arturo: I see now -- I simply assumed (oops) that a global maximum would not be present if every y-value was the same. As for the wording of the question, it was almost identical to the above quote. But I specifically remember the words "no guarantee" in the last sentence, so I believe it's your latter interpretation. Apologies for the useless question. If you post your comment as an answer, I would be glad to accept it. |
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May 11 |
asked | Conditions for a function to have guaranteed global extrema along $[a, b]$ |
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May 7 |
comment |
$\ln(x^2)$ vs $2\ln x$ +1. Thanks for this answer, especially the part about extraneous solutions -- that's something I've been curious about for a while. One of my majors will be math, so hopefully I'll get into more stuff like this in college. It honestly interests me more than the (rather bland) everyday classroom experience I have now. |
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Apr 7 |
awarded | Nice Question |