14,047 reputation
12350
bio website math.brown.edu/~ysolomon
location Providence, RI
age
visits member for 4 years
seen Aug 9 at 0:51

Second-year graduate student at Brown University. Interested in low-dimensional geometry and geometric topology, e.g. Teichmuller theory, Hyperbolic 3-Manifolds, Moduli spaces.


Aug
8
answered Category theory for knot theory
Aug
4
awarded  Yearling
Aug
1
revised What are differences between affine space and vector space?
added 105 characters in body
Aug
1
answered What are differences between affine space and vector space?
Jul
31
comment Example of Something That's Not A Manifold
A manifold is a set with a certain structure, so every set is automatically not a manifold without that structure. Do you mean to ask for topological spaces that aren't manifolds, or subsets of $\mathbb{R}^n$ that aren't manifolds, etc.?
Jul
30
awarded  Disciplined
Jul
20
comment Is this graph connected
Do you think it is important that we know what $\mathcal{R}$ means?
Jul
15
answered Learning Fibre Bundle from “Topology and Geometry” by Bredon
Jul
13
revised Growth restriction for nonnegative, continuous functions whose integrals on $\mathbb{R}$ are bounded
added 489 characters in body
Jul
13
answered Growth restriction for nonnegative, continuous functions whose integrals on $\mathbb{R}$ are bounded
Jul
3
comment Prove that if the induced homomorphism $M/\mathfrak aM \to N/\mathfrak aN$ is surjective, then $f$ it's surjective.
When something is contained in the Jacobson radical and things lift from a quotient, Nakayama's lemma is calling to you.
Jul
3
comment Prove that if the induced homomorphism $M/\mathfrak aM \to N/\mathfrak aN$ is surjective, then $f$ it's surjective.
Do you have Nakayama's Lemma?
Jul
2
awarded  Curious
Jun
21
awarded  Nice Answer
Jun
18
comment Idempotent operators over the exterior algebra
In $A \wedge A = A$, won't the LHS and RHS be forms of different sizes if they aren't zero? I mean, the wedge of two $1$ forms is a $2$ form, so it cannot be a $1$ form unless it is zero.
Jun
18
comment Prove that the Pontryagin dual of a locally compact abelian group is also a locally compact abelian group.
What is your definition of locally compact?
Jun
7
answered The method of proving the equality of integrals by showing they agree within $\epsilon$, for an arbitrary $\epsilon>0$
May
6
awarded  Enlightened
May
6
awarded  Nice Answer
Apr
30
answered Why it is a group action?