meta user
network profile
| bio | website | |
|---|---|---|
| location | UCLA | |
| age | ||
| visits | member for | 2 years, 9 months |
| seen | 6 hours ago | |
| stats | profile views | 1,002 |
I'm currently finishing my undergraduate and masters degrees at UCLA.
Next year I will be a first-year graduate student at Brown.
My interests are broad, but generally speaking, I enjoy problems of a topological (or perhaps geometric) flavor that can be adressed by techniques of analysis and/or algebra. I am also interested in analysis for its own sake.
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2d |
awarded | Constituent |
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May 7 |
awarded | Caucus |
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Apr 25 |
answered | let $f (x) = x^p - a \in F[x]$. Show that $f (x)$ is irreducible over $F$ or $f (x)$ splits in $F$. |
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Apr 23 |
comment |
How can I use prime factorization to find a cube root? You're missing a copy of $2$. $1000 = 2^{3}5^{3}$. |
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Apr 20 |
answered | Question involving improper integrals. |
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Apr 20 |
answered | If $A$ is a diagonalizable $n\times n$ matrix for which the eigenvalues are $0$ and $1$, then $A^2=A$. |
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Apr 18 |
revised |
Is it true that any two tame knots are homotopic? added 9 characters in body |
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Apr 18 |
comment |
Is it true that any two tame knots are homotopic? If you shrink knotted parts to a point, you should remain tame for all $t$. As you shrink the knotted portion, you remain equivalent to a polygonal knot where the lines representing the knotted portion shrink. In the limit, you are equivalent to the unknot, which is very tame! |
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Apr 18 |
revised |
Is it true that any two tame knots are homotopic? added 29 characters in body |
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Apr 18 |
answered | Is it true that any two tame knots are homotopic? |
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Apr 18 |
answered | Function space of a finite set and $\Bbb R^n$ |
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Apr 18 |
comment |
Cubes covering a set in $\mathbb{R^3}$ To put that another way, if you want to estimate the ratio without giving more information about $\Omega$, then your estimation needs to work for all $\Omega$ at once. |
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Apr 18 |
comment |
Cubes covering a set in $\mathbb{R^3}$ Yes, but you don't know what $\Omega$ is. So you can't bound the ratio, because for any bound I can find an $\Omega$ small enough where this bound fails. |
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Apr 18 |
revised |
Cubes covering a set in $\mathbb{R^3}$ added 56 characters in body |
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Apr 18 |
answered | Cubes covering a set in $\mathbb{R^3}$ |
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Apr 14 |
awarded | Nice Question |
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Apr 14 |
answered | Is the product of two measurable subsets of $R^d$ measurable in $R^{2d}$? |
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Apr 13 |
revised |
Doubt on rational and real numbers added 148 characters in body |
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Apr 13 |
answered | Doubt on rational and real numbers |
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Apr 13 |
comment |
What do elements of the first homology group mean topologically? @ZevChonoles : I see you just reached 50k! Congrats. |
