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# 150 Actions

 Sep30 awarded Explainer Feb22 awarded Yearling Aug11 revised How to integrate a Wiener process that freezes at a determined time? Fixed typos Aug11 suggested approved edit on How to integrate a Wiener process that freezes at a determined time? Aug7 comment Sum of two stopping times is a stopping time? There's a typo in the union index, $s$ should be $r$. Other than that I like this answer, because it works also for filtrations that are not necessarily right-continuous and it uses only one auxiliary rational number index. Jul25 revised Conditional expectation proof using definition added 23 characters in body Jul25 answered Conditional expectation proof using definition Jul24 comment You roll a die until the sum of all your rolls is greater than 13. What number are you most likely to land on, on the last roll? Did you mean to ask which of the numbers $14, 15, \dots, 19$ is most likely to be the final sum when the game ends? Then of course $14$ is the answer since it is always one of the possible outcomes, if the next roll has a chance to end the game. Sorry for possibly misunderstanding your question initially. Jul23 comment You roll a die until the sum of all your rolls is greater than 13. What number are you most likely to land on, on the last roll? If your next roll has a chance to push your sum over 13, then 6 is always one of the outcomes that will do it. Therefore 6 is most likely to be your last roll when you start the game. Jul16 comment Probability brainteaser @EmanuelePaolini Why would you ever pay two dollars to play a game where you can only win one dollar? In this game you will either lose one or three dollars, if you pay two to play. Jun1 reviewed No Action Needed Simplifying a quotient of complex numbers Jun1 comment Implications between $\mathbb P [\tau < \infty] =1$ and $\tau \in L_1 (\mathbb P)$ You've identified one problem with your reasoning, but even if that inequality were true I don't see how it would prove that $\tau$ is finite with probability one. May26 revised A basic probability doubt on independence Corrected a typo May26 suggested approved edit on A basic probability doubt on independence May5 comment Naive question about probability @par It's perfectly standard practice to assume a uniform distribution, if one isn't explicitly given. Apr27 awarded Commentator Apr27 comment Probability theory problem Sorry, @Alex, but this is not correct. The correct answer is found after applying Bayes' theorem, but I don't think anyone should give this question a complete answer since it seems to be a verbatim copy of homework and a sloppy one at that. Apr21 revised Change of differentation and integration signs. Corrected spelling and improved formatting Apr21 suggested approved edit on Change of differentation and integration signs. Apr12 answered minimal infinite sigma algebra