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 Jun 9 awarded Informed Jan 12 comment Is it true that the Fibonacci sequence has the remainders when divided by 3 repeating? If (0,0) were visited, wouldn't that mean it would always be 0? Seems that segment must never be visited (assuming you don't start a similar sequence with two multiples of 3). Dec 19 awarded Caucus Dec 19 awarded Constituent Dec 15 awarded Autobiographer Aug 27 comment What is the average of no numbers? I agree that 0 is a sane choice if it needs to be defined - and in practical scenarios, it might need to be. I would also suggest that if you are taking a mean of something with a known or expected population mean, some other value might be a good default to choose, such as said expected mean. Imputation basically works this way - when NaN doesn't suffice, and you need a point for each day, picking a point that makes sense with the other points is a reasonable choice.' Jan 10 comment An oddity in some linear equations Sort of like a binary tree, logically speaking. At the point in which you consider dividing by $x$, what you really do is have a node with two branches. if x≠0 then [divide by x] and if x=0 then [cannot divide by x]. You traverse the first branch, and end up with an absurdity; so that means you know the second branch is the correct branch, at which point you've solved the problem. Jan 7 comment Pedagogy: How to cure students of the “law of universal linearity”? I actually find it easier to explain $(x+3)(x+3) = (x+3)*x + (x+3)*3$. IE, treating the _first_ $(x+3)$ term as a single unit, it becomes identical to $y(x+3)$, which then is easier to understand as $y*x + y*3$. Jan 7 awarded Teacher Jan 7 answered Pedagogy: How to cure students of the “law of universal linearity”? Feb 22 awarded Supporter