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seen Jun 30 '13 at 13:58

"An expert is a person who has made all the mistakes that can be made in a very narrow field." Niels Bohr


Feb
17
revised Injective and Surjective Functions
added 409 characters in body
Feb
17
asked Injective and Surjective Functions
Feb
17
accepted Evaluate $\int \cos^3 x\;\sin^2 xdx$
Feb
14
comment Evaluate $\int \cos^3 x\;\sin^2 xdx$
good to know. thanks
Feb
11
awarded  Editor
Feb
11
revised Evaluate $\int \cos^3 x\;\sin^2 xdx$
added 4 characters in body
Feb
11
comment Evaluate $\int \cos^3 x\;\sin^2 xdx$
integral cos^3(x) sin^2(x) dx = 1/30 sin^3(x) (3 cos(2 x)+7)+constant
Feb
11
asked Evaluate $\int \cos^3 x\;\sin^2 xdx$
Feb
10
accepted Equivalence Relations
Feb
9
comment Equivalence Relations
How would I refer to the ordered pairs then?
Feb
9
asked Equivalence Relations
Jan
29
comment Equivalence Classes of this Relation on the integers : $a + b^2 \equiv 0\pmod{2}$.
I proved it by showing R to be reflexive, symmetric, and transitive. I just don't have much experience with equivalence classes.
Jan
28
comment Equivalence Classes of this Relation on the integers : $a + b^2 \equiv 0\pmod{2}$.
I concur. I probably should have been more specific and noteed that I had already proven that R was an equivalence relation.
Jan
27
awarded  Scholar
Jan
27
accepted Equivalence Classes of this Relation on the integers : $a + b^2 \equiv 0\pmod{2}$.
Jan
27
comment Equivalence Classes of this Relation on the integers : $a + b^2 \equiv 0\pmod{2}$.
But that's not what I asked for
Jan
27
comment Equivalence Classes of this Relation on the integers : $a + b^2 \equiv 0\pmod{2}$.
thanks. so the equivalence class would be the set of all odd integers.
Jan
27
awarded  Student
Jan
27
asked Equivalence Classes of this Relation on the integers : $a + b^2 \equiv 0\pmod{2}$.