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seen Dec 12 '11 at 19:14
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"An expert is a person who has made all the mistakes that can be made in a very narrow field." Niels Bohr


Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
@Tavares, yes it is
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
ok now i see. so then the integral would be sqr[(25x^8)/36 + 1/2 + 9/(100x^8)]
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
@Tavares where does the 1/2 come from?
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
It is 1/(10x^3)
Feb
27
asked Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
Feb
25
comment Number Theory - Proof of divisibility by $3$
ahh i see now. makes perfect sense. thanks
Feb
25
comment Number Theory - Proof of divisibility by $3$
@yunone, how could you prove that 3|x by using x=y(mod 3) if 3|(x-y) only
Feb
25
accepted Number Theory - Proof of divisibility by $3$
Feb
25
comment Number Theory - Proof of divisibility by $3$
@Andres, thanks that helped a lot
Feb
25
awarded  Commentator
Feb
25
comment Number Theory - Proof of divisibility by $3$
Yes i do that if x = y(mod3) then x and y divide 3?
Feb
25
asked Number Theory - Proof of divisibility by $3$
Feb
18
accepted Injective and Surjective Functions
Feb
18
comment Injective and Surjective Functions
thanks. it makes sense to create a proof that includes all possible cases.
Feb
17
comment Injective and Surjective Functions
I edited my proof for a. Please confirm that this is valid.
Feb
17
revised Injective and Surjective Functions
added 409 characters in body
Feb
17
asked Injective and Surjective Functions
Feb
17
accepted Evaluate $\int \cos^3 x\;\sin^2 xdx$
Feb
14
comment Evaluate $\int \cos^3 x\;\sin^2 xdx$
good to know. thanks
Feb
11
awarded  Editor