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seen Jun 30 '13 at 13:58

"An expert is a person who has made all the mistakes that can be made in a very narrow field." Niels Bohr


Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
great. thanks for your help!
Feb
27
accepted Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
Thanks. I finally understand, but shouldn't the evaluated integral be: -1/(10x^3) + x^5/6?
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
how did you get the second qauntity exactly?
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
is there supposed to be a sqr root?
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
@Tavares, yes it is
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
ok now i see. so then the integral would be sqr[(25x^8)/36 + 1/2 + 9/(100x^8)]
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
@Tavares where does the 1/2 come from?
Feb
27
comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
It is 1/(10x^3)
Feb
27
asked Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$
Feb
25
comment Number Theory - Proof of divisibility by $3$
ahh i see now. makes perfect sense. thanks
Feb
25
comment Number Theory - Proof of divisibility by $3$
@yunone, how could you prove that 3|x by using x=y(mod 3) if 3|(x-y) only
Feb
25
accepted Number Theory - Proof of divisibility by $3$
Feb
25
comment Number Theory - Proof of divisibility by $3$
@Andres, thanks that helped a lot
Feb
25
awarded  Commentator
Feb
25
comment Number Theory - Proof of divisibility by $3$
Yes i do that if x = y(mod3) then x and y divide 3?
Feb
25
asked Number Theory - Proof of divisibility by $3$
Feb
18
accepted Injective and Surjective Functions
Feb
18
comment Injective and Surjective Functions
thanks. it makes sense to create a proof that includes all possible cases.
Feb
17
comment Injective and Surjective Functions
I edited my proof for a. Please confirm that this is valid.