Krysten
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 Mar3 comment Determining a closed-form solution for the following sum but when evaluating the first summation, it does not need to be multiplied by (n+1) because you are plugging in for i directly? Mar3 comment Determining a closed-form solution for the following sum in the second summation, are you adding n+1 because the index starts at 0 and not 1? Mar3 revised Determining a closed-form solution for the following sum added 1 characters in body Mar3 comment Determining a closed-form solution for the following sum the second one. Mar3 asked Determining a closed-form solution for the following sum Feb27 comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ great. thanks for your help! Feb27 accepted Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ Feb27 comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ Thanks. I finally understand, but shouldn't the evaluated integral be: -1/(10x^3) + x^5/6? Feb27 comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ how did you get the second qauntity exactly? Feb27 comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ is there supposed to be a sqr root? Feb27 comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ @Tavares, yes it is Feb27 comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ ok now i see. so then the integral would be sqr[(25x^8)/36 + 1/2 + 9/(100x^8)] Feb27 comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ @Tavares where does the 1/2 come from? Feb27 comment Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ It is 1/(10x^3) Feb27 asked Find the length of the curve: $y=\frac{x^{5}}{6}+\frac{1}{10x^{3}}\qquad 1\leq x\leq 2$ Feb25 comment Number Theory - Proof of divisibility by $3$ ahh i see now. makes perfect sense. thanks Feb25 comment Number Theory - Proof of divisibility by $3$ @yunone, how could you prove that 3|x by using x=y(mod 3) if 3|(x-y) only Feb25 accepted Number Theory - Proof of divisibility by $3$ Feb25 comment Number Theory - Proof of divisibility by $3$ @Andres, thanks that helped a lot Feb25 awarded Commentator