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comment Lie and Weierstrass' visualization of complex functions
Over the weekend, I thought up a construction similar to yours. To a complex number $x+iy$ in the functions argument I associate the line connecting $(0,0,-1)$ and $(x,y,0)$. An upward unit vector in the direction of this line acts like your $v$. Like you, I map this line to a member of its orthogonal complement of parallel lines. I orient this complementary space using a vector in the direction of the real axis original complex plane (instead of $n$). But I also have difficulty seeing how this collection of lines in three space provides insight into the behavior of a complex function.
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comment Lie and Weierstrass' visualization of complex functions
I am with you as far as you went, but what then? Something involving a map from the Riemann sphere, as lines, to all the lines in 3-space? Nothing I thought of made much sense. Certainly nothing provided any insight into the function being modeled.
May
12
comment Lie and Weierstrass' visualization of complex functions
@deoxygerbe The quote is on page 41 in either the third (1920) or fourth (1927) edition — the first section of the third chapter.
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revised Lie and Weierstrass' visualization of complex functions
Added Math-History tag to the question
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asked Lie and Weierstrass' visualization of complex functions
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comment Enigma : of Wizards, Dwarves and Hats
I believe the problem statement precludes any communication once the dwarves decide on a strategy or, at least, that is the intention behind the questioners P.S. section.
Apr
22
comment Enigma : of Wizards, Dwarves and Hats
You may want to add that the dwarves need to have absolutely perfect eye sight with infinite resolution and an uncountably infinite capacity to process what they see.
Mar
24
comment Chebyshev center = center of mass?
@lhf: It seems as though there will be lots of diverse and sundry polygons that work. Take a circle and three distinct points on that circle. Imagine three sides of a polygon lying on the tangent lines for the three points. Now connect those three side by inserting any number of sides between them. You need not worry about symmetry. Just make sure that the weight of the sections of the polygon between the three points of tangency balance so that the centroid is the center of the circle. I'd be more hopeful of an interesting result if the circumcenter and centroid were coincident.
Mar
24
comment Dirichlet forms
@Glassjawed As Didier noted, the gradient is defined on edges. The $\frac{1}{2} $ prevents one from double counting the edges when one sums over the vertices.
Mar
23
comment Chebyshev center = center of mass?
Would not a prism formed from a rotationally symmetric polygon work as well provided it was just long enough to make the incenter unique?