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2824
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location Italy
age 48
visits member for 4 years
seen 11 hours ago

Mathematical Physics researcher. Linux user from 1996. C programmer from 1996 to 2002. Mainly oriented to shell programming, package management tools and in general to command line.


2d
awarded  Yearling
Jan
14
revised Integrate rational function with multiple complex roots
added 4 characters in body
Jan
14
comment Integrate rational function with multiple complex roots
@Stefan: sorry, the $D$ was intended as a derivative. I corrected the answer.
Jan
14
revised Integrate rational function with multiple complex roots
added 11 characters in body
Jan
14
revised Integrate rational function with multiple complex roots
added 25 characters in body
Jan
13
answered Integrate rational function with multiple complex roots
Jan
13
revised question about a dot product
added 19 characters in body
Jan
13
reviewed Approve question about a dot product
Jan
13
comment question about a dot product
This does not belong to $C^1[0,1]$.
Jan
13
comment question about a dot product
@jenny: I edited the question for you, let me know if is ok.
Jan
13
revised question about a dot product
added 286 characters in body
Jan
11
revised Surface area of a sphere above the plane $z=1$
edited title
Jan
11
comment Surface area of a sphere above the plane $z=1$
can you show what you did?
Jan
10
comment how can I prove that $\frac{\arctan x}{x }< 1$?
I think that in eq(2) you should suppose $0<x<\pi/2$.
Jan
10
revised how can I prove that $\frac{\arctan x}{x }< 1$?
edited body
Jan
9
comment how can I prove that $\frac{\arctan x}{x }< 1$?
You should show why $x\leq\tan x$.
Jan
6
comment Please explain definition of determinant using permutations?
Why a definition should be derived?
Jan
6
comment How to find $\lim\limits_{x\to0}\frac{e^x-1-x}{x^2}$ without using l'Hopital's rule nor any series expansion?
Why the additional $-2e^t$ on the second line?
Jan
6
revised Implicit assumptions about axes
added 5 characters in body; edited tags
Jan
5
comment Proof of the Intermediate Value Theorem
And the question is ... ?