Jerry Schirmer
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226
Next privilege 250 Rep.
 Jan21 revised Can $1\over 1$, $1\over 2$, $1\over 3$, $1\over 4$, etc. be calculated by the added fractions below? expanded answer Jan21 answered Can $1\over 1$, $1\over 2$, $1\over 3$, $1\over 4$, etc. be calculated by the added fractions below? Jun10 comment Expanding the integrand gives a different result Oh, duh. Yes. Shouldn't math in the morning. Jun10 comment Expanding the integrand gives a different result If you expand the exponential in $\beta$, doesn't that whole term become $\frac{1}{\beta \hbar \omega}$? I don't obviously see why the integral of $\frac{\sin(s\omega)}{\omega^{2} + \gamma^{2}}$ is zero. May7 comment Adding sin(x + a) + sin(x + b) I will say that choosing those particular points is potentially not optimal. The key is to get the sine to take known values. It might also be prudent to shift your overall equation before you start, so you can eliminate $a$ or $b$, i.e., by defining $z = x+a$, and then defining $\beta = b -a$, and $\delta = d - a$ so you have fewer constants to worry about. May7 comment Adding sin(x + a) + sin(x + b) @mafutrct: I have to admit that it's been years since I've done this, but I have solved this identity this way when proving circuit results to class. May6 answered Adding sin(x + a) + sin(x + b) Mar15 awarded Yearling Feb8 comment Replacing large-dimensional ODE systems with one PDE @SergioParreiras: see edit. Feb8 revised Replacing large-dimensional ODE systems with one PDE added 444 characters in body Dec18 awarded Supporter Apr2 comment computing the $y_{cm}$ Also, I would recommend not carrying around your denominator. What should your answer for $\int dm$ be? Mar26 answered Replacing large-dimensional ODE systems with one PDE Mar1 comment Change of Variables in a 3 dimensional integral Hint: try calculating the volume of a sphere in Cartesian and in Spherical coordinates. Feb13 comment Divergence theorem on Hyperbolic space @PML: it works in both cases. The minkowski case is cleaner, since the $r,\phi,\theta$ system is orthonormal in the minkowski case. If you embed in Euclidean space, though, you will still find that $\sqrt{\rm det g} = r^{2}\sinh\phi d\theta d\phi$, you'll just have to content with $g_{r\phi}$ components to your metric tensor. Feb12 awarded Editor Feb12 revised Divergence theorem on Hyperbolic space added 8 characters in body Feb11 awarded Teacher Feb11 answered Derivative of a factorial Feb11 answered Divergence theorem on Hyperbolic space