186,251 reputation
17129289
bio website
location
age
visits member for 3 years, 9 months
seen 6 mins ago

As somebody used to say:

Does research. Smokes. Battles administration. Smokes. Wishes he could stop battling administration so that he could have more time to do research. Smokes some more.

The same. Except I do not smoke.


How to ask a good question?

This paragraph is for my personal use but freely available:

Welcome to Math.SE! Please, consider updating your question to include what you have tried and where you are getting stuck. That way, people on this site will know exactly what help you need.


1h
answered how to find the smallest s to make f continuous at (0,0)
1h
answered Expectation of a powered complex circular gaussian process
1h
answered Lyapunov exponent for simple functions
1d
answered What is acceptable set of values $E[ \max(X-4,0)]$?
1d
answered Variance of stochastic process $MA(2)$
1d
answered Understanding sigma super additivity
1d
answered Probability Assignment to Intervals in $\mathbb{R}^{n}$.
1d
answered Is there a mistake in this page on asymptotic expansions?
1d
answered Relationship “finite mean” <-> "absolutely integrable
1d
answered Help with proof of expected value of gamma distribution
1d
answered Show $\sum_n \left(1-\frac{K}{n^{1-\epsilon}\sqrt{\log n}} \right)^n$ converges for $\epsilon>0$.
1d
answered Solving recurrence with non constant coefficients
2d
answered Prove that $ \lim_{n \to \infty} \frac{\Phi(- \sqrt{n})}{f(\sqrt{n})} = 1$.
2d
answered Using the binomial distribution as the distribution for a sum of Bernoulli random variables?
2d
answered Does $E(|X_n - X|) \rightarrow 0$ implies $X_n$ converges in probability to $X$?
2d
answered prove that this equality is always right for each positive x and y.
2d
answered Rate of convergence of $\left[ \left( \sum\limits_{i=j}^n {2i+1}\right)^{\frac{1}{2}}\right]$
2d
answered Prove the inequality$\int_0^{+\infty} {\sin x \over x}dx<\int_0^\pi {\sin x \over x}dx$
2d
answered How to derive this inequality
2d
answered The sequence $\sin \left({n\pi}\over 6\right)$ has the superior limit $L=1\dots$