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Mar
14
comment Distribution of the maximum minus the minimum
No. (Any source for what you write?)
Mar
14
comment Distribution of the maximum minus the minimum
Define lack of memory, which involves one random variable, and compare to what you write, which involves two random variables.
Mar
14
comment Distribution of the maximum minus the minimum
Pure nonsense, sorry. The fact that the minimum is exponential does not imply this, in any way.
Mar
14
comment Distribution of the maximum minus the minimum
This is becoming a little tiresome... No there is no "distribution of n-1 random variable(s)" in my answer (so what are you talking about?) and unless you explain precisely why you think that Markov property and lack of memory should be "related" (which you don't at the moment), what can I say? The things you seem to believe are most certainly at least partly wrong but you have to be much more specific if you want somebody to debunk them.
Mar
14
comment Criterion of independent random vectors
The WP link shows both claims in your post are wrong. So, you are not using any textbook?
Mar
14
comment Distribution of the maximum minus the minimum
No it is not. Please see added paragraph at the end of my answer.
Mar
14
revised Distribution of the maximum minus the minimum
added 275 characters in body
Mar
14
comment Distribution of the maximum minus the minimum
Did you read my comment to the question? Please do. The statement you quote does not even mention the name "Markov".
Mar
14
comment Two random variables from the same probability density function: how can they be different?
The Edit should answer these.
Mar
14
revised Two random variables from the same probability density function: how can they be different?
added 805 characters in body
Mar
13
revised Are there hidden events?
added 88 characters in body
Mar
13
answered Two random variables from the same probability density function: how can they be different?
Mar
13
answered Are there hidden events?
Mar
13
comment Criterion of independent random vectors
Tell me. $ $ $ $
Mar
13
comment Criterion of independent random vectors
Both wrong, as your textbook takes pains to explain.
Mar
13
comment Is this a poorly worded probability question? Unsolvable?
@user130512 Yes I know this is what you are doing, and I object to it. The FIRST piece of information to provide is that the question does not make sense as stated.
Mar
13
comment Is this a poorly worded probability question? Unsolvable?
@user130512 "the assumption one makes is that the probabilities are independent" Do we make this assumption? Do we wish to make it? Does it make sense to make it?
Mar
13
answered Expectation of a product of (many) 1-dimensional Brownian motions.
Mar
13
answered How find this sum $f(n)=\sum_{i=1}^{n}\dfrac{\binom{n}{i}}{i}$
Mar
13
comment Is a non-negative random variable with zero mean almost surely zero?
How did you define E(X) then?