# Ayush Khemka

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bio website stumbleupon.com/ayushkhemka location Mumbai, India age 21 member for 10 months seen Sep 20 at 5:09 profile views 8

I am a web development enthusiast.

# 30 Actions

 Jul23 answered Differentiating $\tan\left(\frac{1}{ x^2 +1}\right)$ Jul23 comment Differentiate $\sin \sqrt{x^2+1}$with respect to $x$? Oh yes, and I think I used $x$ instead of $\sqrt {x^2+1}$. I'm so sorry for that! Jul23 comment Differentiate $\sin \sqrt{x^2+1}$with respect to $x$? The edits are accepted, they're right. But that was the way I was taught in school (back in the eleventh grade I guess), to work in functions rather than substitute variables, probably to make things easier for us back then. So, thank you everyone for your suggestions/reviews. Jul23 answered Differentiate $\sin \sqrt{x^2+1}$with respect to $x$? May31 revised Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ deleted 2 characters in body May31 revised Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ added 7 characters in body May31 comment Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ oh well, ok i'll do that, think it has the same meaning though May31 revised Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ deleted 5 characters in body May31 comment Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ ok, i'll put it, thanks May30 answered Given $\int _0 ^{+ \infty} \frac{1}{(1+x)^a} =1, \ \ a =?$ May29 awarded Analytical May29 answered How do you divide a complex number with an exponent term? May2 answered Solve for $x$: question on logarithms. Apr20 awarded Supporter Feb22 awarded Autobiographer Feb19 answered Evaluate $\int {2x\over x^2-1}dx$ Feb19 comment Find $\int e^{-x}\cos x\,dx$ without using complex numbers edited it, thanks for the reply! Feb19 revised Find $\int e^{-x}\cos x\,dx$ without using complex numbers Proved step 2 Feb19 comment Find $\int e^{-x}\cos x\,dx$ without using complex numbers I think this answer here can help you prove that math.stackexchange.com/a/138269/61588 Feb19 answered Find $\int e^{-x}\cos x\,dx$ without using complex numbers