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 Apr 24 awarded Notable Question Nov 18 awarded Popular Question Mar 3 accepted Matrix Exponential using JNF and transition Matrix Mar 2 asked Matrix Exponential using JNF and transition Matrix Feb 20 awarded Scholar Feb 20 accepted Algebraic and geometric multiplicity, eigenspace and Transition Matrix Feb 19 comment Algebraic and geometric multiplicity, eigenspace and Transition Matrix ohhh okay i understand it now :) thankyouuuuu :D Feb 19 comment Algebraic and geometric multiplicity, eigenspace and Transition Matrix so in my question, using my eigenvalues $2$ and $3$ what would my eigenspaces be? Feb 19 comment Algebraic and geometric multiplicity, eigenspace and Transition Matrix @GitGud one last quick question, what is the eigenspace? Feb 19 awarded Commentator Feb 19 awarded Editor Feb 19 comment Algebraic and geometric multiplicity, eigenspace and Transition Matrix i think i understand, the geometric multiplicity is 1 for both values of $\lamda$ as they both produce only one eigenvector each? Feb 19 revised Algebraic and geometric multiplicity, eigenspace and Transition Matrix added 23 characters in body Feb 19 comment Algebraic and geometric multiplicity, eigenspace and Transition Matrix yes this is clearer, this is the same for the geometric multiplicity? so they'd both be 1?? as in are they relitive to each eigenvector? Feb 19 comment Algebraic and geometric multiplicity, eigenspace and Transition Matrix so in this case, the algebraic multiplicity would be 2? as it is the largest $k$ value? .... i've memorised the method of computing the JNF so i dont exactly understand it, however now im currently attempting to understand it Feb 19 awarded Student Feb 19 asked Algebraic and geometric multiplicity, eigenspace and Transition Matrix Feb 6 comment For a normally distributed random variable, find a value from given tail probability ohhh sorry musta been a typo, thankyou i understand it now. And that other explanation is AMAZING :) Feb 6 comment For a normally distributed random variable, find a value from given tail probability im not 100% sure where i've gone wrong with my working out? Feb 6 comment For a normally distributed random variable, find a value from given tail probability @StefanHansen i've gotten to $\frac {x-65}{2(5)^{1/2}} =0.1764$ and hence $x = 67.789$ ??