MrsMillz
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 Sep24 awarded Autobiographer Feb9 awarded Supporter Feb9 comment Exhibit a bijection between $\mathbb{N}$ and all odd $\mathbb{Z}$ greater than 13. Deinitely would not have thought of it this way. I need to let it sit for a bit, then come back to it. Thanks! Feb8 comment Exhibit a bijection between $\mathbb{N}$ and all odd $\mathbb{Z}$ greater than 13. Start with Let $f(m) \in \mathbb{Z}$ such that $f(m)=2n+1$ or should it be $2n+13$ in this case? The hardest part for me seems to be starting a proof. Once I get it rolling, I'm usually okay. Feb8 comment Exhibit a bijection between $\mathbb{N}$ and all odd $\mathbb{Z}$ greater than 13. I meant $2n + 13$. Shoot! Feb8 revised Exhibit a bijection between $\mathbb{N}$ and all odd $\mathbb{Z}$ greater than 13. meant 2n + 13 ! Feb8 comment Exhibit a bijection between $\mathbb{N}$ and all odd $\mathbb{Z}$ greater than 13. Do you mean odds represented as $2n+1$, and work backwards somehow? Feb8 asked Exhibit a bijection between $\mathbb{N}$ and all odd $\mathbb{Z}$ greater than 13. Feb8 answered Which Mathematical Analysis I Book or Textbook Is The Best? Feb3 revised Showing inverse composed with function is $x$ for all $x$ in the domain. improved formatting, offered questionable answer Feb3 awarded Editor Feb3 revised Showing inverse composed with function is $x$ for all $x$ in the domain. improved formatting Feb3 awarded Student Feb3 comment Showing inverse composed with function is $x$ for all $x$ in the domain. (Again, I apologize, I'm trying to learn how to code this, and don't have a clue!). Inverse: If f mapping A onto B is a bijection of A onto B, then g:={(b, a) element of BxA: (a,b) element of f} is a function of B into A. Feb3 asked Showing inverse composed with function is $x$ for all $x$ in the domain.