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I am a first year graduate student at Princeton university interested in Analytic Number Theory and Additive Combinatorics.

You can contact me at naslund [at] math [dot] princeton [dot] edu, or visit my website for more information.


1d
awarded  convergence
1d
awarded  Nice Answer
2d
answered Divergence of $\sum \frac{a_j}{1+a_j}$
2d
comment Prime Counting: Relationship between Chebyshev's function and the Prime counting function
I believe that this question (or similar) has been answered before on MSE, but I could not find it.
2d
answered Prime Counting: Relationship between Chebyshev's function and the Prime counting function
Apr
18
comment Applications of generating functions to number theory
The Hardy-Littlewood circle method.
Apr
17
revised Expected number of rolls when repeatedly rolling an $n$-sided die
edited title
Apr
17
comment Is this summation solvable? $S_n = \sum_{i = 1}^{n}\log_i{(n)}$
@Joel: Corrected, thanks.
Apr
17
revised Is this summation solvable? $S_n = \sum_{i = 1}^{n}\log_i{(n)}$
edited body
Apr
17
revised Stirling Numbers of the First Kind and $S_n$.
added 440 characters in body
Apr
17
answered Stirling Numbers of the First Kind and $S_n$.
Apr
17
revised Is this summation solvable? $S_n = \sum_{i = 1}^{n}\log_i{(n)}$
added 463 characters in body
Apr
17
answered Is this summation solvable? $S_n = \sum_{i = 1}^{n}\log_i{(n)}$
Apr
17
revised Expected number of rolls when repeatedly rolling an $n$-sided die
deleted 4 characters in body
Apr
17
answered Expected number of rolls when repeatedly rolling an $n$-sided die
Apr
11
awarded  Announcer
Apr
8
comment Show that $A_n=\sum\limits_{k=1}^n \sin k $ is bounded?
@Ant: Yes it does. I recommend working out the details for yourself.
Apr
8
answered Bounding this arithmetic sum
Apr
8
comment Show that $A_n=\sum\limits_{k=1}^n \sin k $ is bounded?
@Ant: The question asked to show that $\sum_{n=0}^k \sin(n)$ is bounded for all $k$. Boundedness is a less stringent condition than convergence. (All convergent sequences are bounded but not vice versa)
Apr
8
comment Show that $A_n=\sum\limits_{k=1}^n \sin k $ is bounded?
@Ant: It's a finite series so it does converge. It is true that the infinite series $\sum_{n=1}^\infty e^{inx}$ does converge, but that is not what appears here.