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 Feb 12 comment Is it possible to find a 2D distribution function such that the higher order moments always exist? And can we ensure those moments are always non-zero even if the support is possitive i.e., for the supports [a,b] and [c,d]? Feb 12 asked Is it possible to find a 2D distribution function such that the higher order moments always exist? Oct 15 awarded Teacher Aug 20 comment How many unit hexagonal tiles can be placed inside a larger hexagon of sides $a,b,c,a,b,c$? And thanks a lot for answering the philosophical questions. To Read: Martin Gardner's math books is on my to do list :-) What an awesome community by the way! Aug 20 accepted How many unit hexagonal tiles can be placed inside a larger hexagon of sides $a,b,c,a,b,c$? Aug 20 comment How many unit hexagonal tiles can be placed inside a larger hexagon of sides $a,b,c,a,b,c$? Brilliant illustration. I loved it. I get it now. The number of tiles on the visible faces is (ab+bc+ca). Then the number of tiles that have been counted multiple times in the previous product (a+b+c) + 1 (the tile at the intersection of the red, green and blue lines). Voilà. Aug 19 comment How many unit hexagonal tiles can be placed inside a larger hexagon of sides $a,b,c,a,b,c$? oops. Sorry Sir.My fault.I have removed that comment saying your answer is wrong. Now, I have upvoted your answer. Although before accepting your answer, i would like to clarify the logic behind. So, $a+(a+1)+...$ is the number of unit hexagons in 1 trapezoid. right? This is an arithmetic progression. How did you find out the last term (a+b-1)? Second, I dont understand how you arrived at $(c−b−1)(a+b−1)$? One more thing is about your assumption. The formula works even when your assumption is violated. a = 985;b=2;c=2 Aug 19 revised How many unit hexagonal tiles can be placed inside a larger hexagon of sides $a,b,c,a,b,c$? have added some test cases for answerers to check their cases before they post Aug 19 comment How many unit hexagonal tiles can be placed inside a larger hexagon of sides $a,b,c,a,b,c$? hmm.thanks for your quick response. But Sorry the answer is wrong. For a=7,b=8,c=13, the correct answer is 224. Your expression gives 84. Aug 19 awarded Commentator Aug 19 comment How many unit hexagonal tiles can be placed inside a larger hexagon of sides $a,b,c,a,b,c$? @copper.hat: I dont get it. How does a>1 remove tiles? Aug 18 asked How many unit hexagonal tiles can be placed inside a larger hexagon of sides $a,b,c,a,b,c$? Jul 23 comment Multi binomial theorem application yes. I did mean that $v<=alpha$. term. thanks. I got it. But still not sure of how to proceed with the expansion. Jul 23 comment Multi binomial theorem application Thats what i m not sure. Under the assumptions that i have given, we can approximate each of the terms above as (a1/c1)x+(b1/c1)y+1. So should i expand it using multi multinomial theorem? Jul 23 revised Multi binomial theorem application added 177 characters in body; edited title Jul 23 asked Multi binomial theorem application Apr 19 comment Computing the moments of a triangle right! but do you know if i can find a copy of that file somewhere or if you have one, i ll be glad to take it. Apr 19 comment Computing the moments of a triangle The second link is not working.. Oct 28 comment Odd order moments of a symmetrical distribution that was superb! Oct 14 comment Symbolic computation of the derivative of dot product of 2 vectors @Bill Cook: Thank you. I tried using what you ve sent me. The expressions seem to be complicated though. Well. fair enough. But i was wondering if i could retain a and b and its derivatives a' and b' (w.r.t time)as vectors itself in the final expression.