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 2d comment Simple Logarithmic question. thank you for answering my question. 2d comment Simple Logarithmic question. perhaps that's the answer my book has, but i cant do that in my head... 2d comment Simple Logarithmic question. 3 twos means log base 3 will give you a two one 3 means logs base 3 will give you a cubic root of 3 but im not sure if i can do that or not. 2d asked Simple Logarithmic question. Mar17 awarded Popular Question Jan31 awarded Yearling Jan5 awarded Famous Question Jan3 awarded Custodian Jan2 accepted Prove that if a set A of natural numbers contains $n_0$ and whenever A contains k it also contains k+1. Jan2 comment Prove that if a set A of natural numbers contains $n_0$ and whenever A contains k it also contains k+1. Oh! Thank you for taking the time to re-write that I totally follow how it proves it for all values now. Jan2 accepted Difficulty involving Rings and Subrings Proving lub contained in fields? Jan2 accepted Absolute convergence. Jan2 accepted continiouty of maping from set back into itself. Jan2 accepted Does this proof work? Jan2 comment Prove that if a set A of natural numbers contains $n_0$ and whenever A contains k it also contains k+1. Thank you that makes perfect sense. Jan2 comment Prove that if a set A of natural numbers contains $n_0$ and whenever A contains k it also contains k+1. Me defining D in Case 1 just makes it easy to prove that $A_1 \ cup B =$ natural numbers as $A_1 \ cup B$ says with words Exactly the same thing as the Set D Jan2 comment Prove that if a set A of natural numbers contains $n_0$ and whenever A contains k it also contains k+1. Very sorry Someone Edited my post and moved the Statement around to make no sense at all i put it back to what it originally said. Jan2 revised Prove that if a set A of natural numbers contains $n_0$ and whenever A contains k it also contains k+1. added 19 characters in body Jan2 comment Prove Bernoulli inequality if $h>-1$ Thats very clever I really like that approach thanks! Jan2 asked Prove that if a set A of natural numbers contains $n_0$ and whenever A contains k it also contains k+1.