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Apr
27
comment Random Walk - If $m$ is odd, probability of no equalization in the last $m$ steps in path of length $2m$ is 1/2
Got it. Thanks
Apr
27
comment Random Walk - If $m$ is odd, probability of no equalization in the last $m$ steps in path of length $2m$ is 1/2
I didn't get how $$\sum_{r=0}^m \Pr[T = 2r] = 1$$ Other than this step I can follow the argument. Thanks.