| bio | website | |
|---|---|---|
| location | Ulm, Germany | |
| age | ||
| visits | member for | 3 months |
| seen | yesterday | |
| stats | profile views | 16 |
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May 15 |
asked | Is $\varphi:x \mapsto A\cdot x$ an orthogonal projection for M |
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May 6 |
accepted | Find matrices $S$ and $Q$ which satisfy $B = S^t AS$ and $A=Q^tQ$ |
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May 6 |
comment |
Find matrices $S$ and $Q$ which satisfy $B = S^t AS$ and $A=Q^tQ$ Thanks again.. I was so overworked, I mixed up the Letters. |
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May 5 |
comment |
Find matrices $S$ and $Q$ which satisfy $B = S^t AS$ and $A=Q^tQ$ Thanks for your answer. The first part helped my really. But I am not sure, how to adopt your number 2. for $B=Q^TIQ$ |
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May 5 |
comment |
Find matrices $S$ and $Q$ which satisfy $B = S^t AS$ and $A=Q^tQ$ Sorry forgot to add that. I did now edit my question, to include the definition. |
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May 5 |
revised |
Find matrices $S$ and $Q$ which satisfy $B = S^t AS$ and $A=Q^tQ$ added 38 characters in body |
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May 5 |
asked | Find matrices $S$ and $Q$ which satisfy $B = S^t AS$ and $A=Q^tQ$ |
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May 5 |
accepted | Gram-Schmidt procedure gives null vector as solution. |
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May 4 |
comment |
Gram-Schmidt procedure gives null vector as solution. This check must also hold true for my resulting vectors, right? |
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May 4 |
awarded | Editor |
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May 4 |
revised |
Gram-Schmidt procedure gives null vector as solution. added 3 characters in body |
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May 4 |
comment |
Gram-Schmidt procedure gives null vector as solution. @StefanSmith Thanks for your comment, I do appreciate it. My impreciseness, is due to me not being a native speaker. So I hear my lectures in German. I try to give my best, to find the right terminology. Additionally I am kind of an newbie, with different background, trying to wrap my head around all those things I hear in the math lectures. |
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May 3 |
awarded | Student |
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May 3 |
comment |
Gram-Schmidt procedure gives null vector as solution. thanks to you two. So I have to choose a different starting set. But how can I check afterwards whether my solution is correct? |
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May 3 |
asked | Gram-Schmidt procedure gives null vector as solution. |
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Apr 27 |
asked | decomposition of m-cycle in m-1 transpositions |
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Apr 22 |
comment |
Permutations and Equivalence Relations does your point 2 apply if k has to be >= 0 ? |
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Mar 31 |
awarded | Scholar |
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Mar 31 |
accepted | Tolling “Whats the next number of this sequence” |
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Mar 26 |
asked | Tolling “Whats the next number of this sequence” |