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Jun
10
comment My sister absolutely refuses to learn math
You're evil :) But I like your style
May
30
awarded  Autobiographer
Apr
8
awarded  Citizen Patrol
Jan
24
awarded  Scholar
Jan
24
awarded  Supporter
Jan
24
accepted What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$
Jan
23
comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$
Ok, so I tried a few stuff (law of sines), since it kind of makes sense in this situation. But not sure how to proceed from here on, any tips?
Jan
23
revised What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$
trying to answer
Jan
23
comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$
I think so, but I haven't worked with vectors for some time, so I may need a bit of reminding :P
Jan
23
awarded  Student
Jan
23
awarded  Editor
Jan
23
revised What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$
added 9 characters in body
Jan
23
comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$
I think it's: each PI - alpha/2
Jan
23
comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$
I don't know, this is how I found the "problem" in multiple places ( here's one: wiki.answers.com/Q/… ), including the typo ant instead of and
Jan
23
awarded  Custodian
Jan
23
comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$
Reformatted. This being my first post, I don't know all the formatting rules yet, sorry.
Jan
23
reviewed Approve What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$
Jan
23
asked What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$