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 Jun10 comment My sister absolutely refuses to learn math You're evil :) But I like your style May30 awarded Autobiographer Apr8 awarded Citizen Patrol Jan24 awarded Scholar Jan24 awarded Supporter Jan24 accepted What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$ Jan23 comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$ Ok, so I tried a few stuff (law of sines), since it kind of makes sense in this situation. But not sure how to proceed from here on, any tips? Jan23 revised What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$ trying to answer Jan23 comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$ I think so, but I haven't worked with vectors for some time, so I may need a bit of reminding :P Jan23 awarded Student Jan23 awarded Editor Jan23 revised What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$ added 9 characters in body Jan23 comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$ I think it's: each PI - alpha/2 Jan23 comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$ I don't know, this is how I found the "problem" in multiple places ( here's one: wiki.answers.com/Q/… ), including the typo ant instead of and Jan23 awarded Custodian Jan23 comment What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$ Reformatted. This being my first post, I don't know all the formatting rules yet, sorry. Jan23 reviewed Approve What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$ Jan23 asked What is $(z_2-z_3)^2 = 4(z_3-z_1)(z_1-z_2) \sin^2\frac{\alpha}{2}$