Alan C
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 Apr11 asked Transpose of a linear operator on functions Feb17 awarded Popular Question Jan30 awarded Enthusiast Jan23 revised Alternative to Axler's “Linear Algebra Done Right” edited tags Jan22 awarded Nice Answer Jan22 comment Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle @vincentbelkin, I edited my answer. Jan22 comment Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle @AsafKaragila, thanks! Jan22 revised Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle edit in response to follow up question Jan22 revised Derivative for log improved formatting, capitalization Jan22 suggested approved edit on Derivative for log Jan22 awarded Editor Jan22 revised Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle added more info relevant to the question Jan22 revised Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle improved formatting Jan22 answered Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle Jan22 suggested approved edit on Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle Jan16 awarded Yearling Jan10 accepted Defining the determinant of linear transformations as multilinear alternating form Jan3 accepted Is there a geometric argument that the Legendre transform of a convex function is convex? Oct7 asked Is there a geometric argument that the Legendre transform of a convex function is convex? Sep1 comment Is there a simple way to bound this contour integral? Thanks for your comment. I realized that I was having a hard time phrasing my question. Now that I think about it, I wanted to be able to get a sharper estimation - I wanted to be able to get a feel for how $\int e^{-R^2 \cos2\theta} R \, d\theta$ behaves for large values of $R$ (even though to evaluate the original integral, we just needed to show this was $o(1)$). But like you said, this estimation isn't too bad. How did you get that estimate of yours?