Alan C

less info
meta site favicon meta user | stack exchange network profile network profile
565 reputation
311
bio website learn2cube.com
location
age
visits member for 2 years, 4 months
seen 3 hours ago
stats profile views 40

64 Actions

suggestions reviews revisions comments badges posts accepts all
May
6
 awarded  Caucus
Apr
14
 accepted Transpose of a linear operator on functions
Apr
11
 comment Transpose of a linear operator on functions
Ah, thanks! I was thinking of using the divergence theorem, but I wasn't sure if it was applicable (partly because I didn't know what was the exact space of functions $L$ was acting on).
Apr
11
 asked Transpose of a linear operator on functions
Feb
17
 awarded  Popular Question
Jan
30
 awarded  Enthusiast
Jan
23
 revised Alternative to Axler's “Linear Algebra Done Right”
edited tags
Jan
22
 awarded  Nice Answer
Jan
22
 comment Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle
@vincentbelkin, I edited my answer.
Jan
22
 comment Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle
@AsafKaragila, thanks!
Jan
22
 revised Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle
edit in response to follow up question
Jan
22
 revised Derivative for log
improved formatting, capitalization
Jan
22
 suggested suggested edit on Derivative for log
Jan
22
 awarded  Editor
Jan
22
 revised Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle
added more info relevant to the question
Jan
22
 revised Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle
improved formatting
Jan
22
 answered Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle
Jan
22
 suggested suggested edit on Why is $y = \sqrt{x-4}$ a function? and $y = \sqrt{4 - x^2}$ should be a circle
Jan
16
 awarded  Yearling
Jan
10
 accepted Defining the determinant of linear transformations as multilinear alternating form
1 2 3 4