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seen May 12 '13 at 23:30

May
10
awarded  Scholar
May
10
awarded  Supporter
May
10
accepted Computing $a^r \bmod n$ for a real number $r < 1$
May
10
accepted Modulo in e-voting paper is wrong?
May
10
comment Modulo in e-voting paper is wrong?
Excellent answer. I am choosing it as best answer. Thank you!
May
10
comment Modulo in e-voting paper is wrong?
@TMM I can not understand why 17^1/121 is 15. Isn't it the same with 17^17 which makes 240?
May
10
comment Modulo in e-voting paper is wrong?
@TMM thank you. I'll find what I am doing wrong now
May
10
comment Modulo in e-voting paper is wrong?
I get d= 17 and e = 240...
May
10
comment Computing $a^r \bmod n$ for a real number $r < 1$
@TMM Thanks a lot. I haven't found however any solution at my specific problem, if you want to take a look math.stackexchange.com/questions/387827/… . I do not have enough reputation yet to upvote your answer. If I get some, I'll upvote it for sure. :)
May
10
comment Computing $a^r \bmod n$ for a real number $r < 1$
Thanks a lot. I haven't found however any solution at my specific problem, if you want to take a look math.stackexchange.com/questions/387827/… . I do not have enough reputation yet to upvote your answer. If I get some, I'll upvote it for sure. :)
May
10
asked Modulo in e-voting paper is wrong?
May
10
comment Computing $a^r \bmod n$ for a real number $r < 1$
Thank you. However that's kind of strange... If I have the number 100 and the number 257 is my modulo number, then how I can choose the powers, in order to get number 100 bavk, when I apply these two powers?
May
10
comment Computing $a^r \bmod n$ for a real number $r < 1$
@TMM Thank you. However, when I try to do the equation above at the website ptrow.com/perl/calculator.pl it gives me 141 as final result instead of 100. The same does the program I have written as well (141 too!). I do not know what I am doing wrong...
May
10
comment Computing $a^r \bmod n$ for a real number $r < 1$
@TMM Thank you very much. I was (and am) a little confused. If I have (100 ^ 121) mod 257 then ((100 ^ 121) mod 257) ^ (1/121) mod 257 than the result of the second equation is equal to 100?
May
10
awarded  Commentator
May
10
comment Computing $a^r \bmod n$ for a real number $r < 1$
Thank you very much. I was (and am) a little confused. If I have (100 ^ 121) mod 257 then ((100 ^ 121) mod 257) ^ (1/121) mod 257 than the result of the second equation is equal to 100?
May
10
comment Computing $a^r \bmod n$ for a real number $r < 1$
@TMM Thank you. I will try it now, and I will tell you if I can do this works. Thanks again
May
10
asked Computing $a^r \bmod n$ for a real number $r < 1$
Feb
19
awarded  Analytical
Jan
20
comment Interpolation problem
@TMM yes, indeed, but how i can solve matrices with mod