Ernest Singleton
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 Oct28 awarded Popular Question Jul2 awarded Curious Apr13 accepted Inner product spaces that are isometrically isomorphic Apr13 asked Inner product spaces that are isometrically isomorphic Mar10 comment Riemann-Stieltjes integrability question Thanks, makes perfect sense. Mar10 accepted Riemann-Stieltjes integrability question Mar9 asked Riemann-Stieltjes integrability question Jan30 comment On building a subsequence inductively Gotcha. You've been a great help Brian. Jan30 comment On building a subsequence inductively Alternatively, if the lim sup of a sequence diverged to $-\infty$, could we prove that this sequence had a subsequence that diverged to $-\infty$ by ensuring that $s_{n_k}$ is less than $k$, for every $k$? Jan30 comment On building a subsequence inductively Oh. I was just misinterpreting your notation. But I think I understand now: you are just saying we should take $n_{k+1}$ to be the smallest integer such that both those conditions are satisfied. Jan30 comment On building a subsequence inductively Hey Brian, I'm a little confused as to why you would take the minimum of those integers in choosing $n_{k+1}$. Jan30 accepted On building a subsequence inductively Jan29 asked On building a subsequence inductively Jan26 awarded Supporter Jan24 comment If $AB=BA$, show that $B$ is diagonalizable. I understand now. Thank you very much. I just wasn't considering the one dimensionality of the eigenspace. Thank you very much Jonas. Jan24 accepted If $AB=BA$, show that $B$ is diagonalizable. Jan24 comment If $AB=BA$, show that $B$ is diagonalizable. Hey Jonas, I still don't understand how it is that if $v$ is an eigenvalue of $A$ corresponding to some eigenvalue $\lambda$, that $A(Bv)= \lambda Bv$ implies that $v$ is also an eigenvector of $B$. I was wondering if you could clear that up for me. Thanks. Jan24 awarded Scholar Jan24 accepted Distance in at most countable metric spaces Jan24 asked If $AB=BA$, show that $B$ is diagonalizable.