Paul Raff
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 Apr 7 comment Intuitive explanation for why $\left(1-\frac{1}{n}\right)^n \to \frac{1}{e}$ @Yves Daoust is making an excellent point here. You can't just say that because it's less that one/greater than one, that's why the limit remains like that. In Yves' example, that limit is 1: wolframalpha.com/input/…. Dec 28 answered Standard Error Loss vs. Absolute Loss Dec 28 revised Standard Error Loss vs. Absolute Loss Corrected probable typo. Dec 28 suggested approved edit on Standard Error Loss vs. Absolute Loss Dec 28 answered Prove that $5^n + 2\cdot3^{n-1} + 1$ is multiple of $8$ Jan 17 awarded Yearling Jan 17 awarded Yearling Feb 7 awarded Nice Answer Feb 7 answered The number of ways of selecting $n$ cards out of unlimited number of cards bearing the number $0,9,3$ Feb 6 revised Independence of a certain Linear combination of random variables Made it more accurate to talk about independence in the title Feb 6 comment limit ${\lim_{x \to 49} \frac{\sqrt{x}-7}{x-49} }.$ It's a stretch for most people to think of $x - 49$ as something that can be expressed in the form $a^2 - b^2$. Feb 6 suggested approved edit on Independence of a certain Linear combination of random variables Feb 6 comment limit ${\lim_{x \to 49} \frac{\sqrt{x}-7}{x-49} }.$ I don't think this helps to understand the problem in a way for the asker to apply in the future. Feb 6 answered limit ${\lim_{x \to 49} \frac{\sqrt{x}-7}{x-49} }.$ Feb 6 answered Why, given a natural number $n$, does $n^6$ always have the remainder of 1 when divided by 7? Jan 25 awarded Critic Jan 25 answered If there exists a function that maps A onto B , show that A is also uncountable Jan 21 answered European Calls: arbitrage Jan 21 awarded Organizer Jan 21 revised European Calls: arbitrage It's a homework problem