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 Yearling
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Apr
7
comment Intuitive explanation for why $\left(1-\frac{1}{n}\right)^n \to \frac{1}{e}$
@Yves Daoust is making an excellent point here. You can't just say that because it's less that one/greater than one, that's why the limit remains like that. In Yves' example, that limit is 1: wolframalpha.com/input/….
Dec
28
answered Standard Error Loss vs. Absolute Loss
Dec
28
revised Standard Error Loss vs. Absolute Loss
Corrected probable typo.
Dec
28
suggested approved edit on Standard Error Loss vs. Absolute Loss
Dec
28
answered Prove that $5^n + 2\cdot3^{n-1} + 1$ is multiple of $8$
Jan
17
awarded  Yearling
Jan
17
awarded  Yearling
Feb
7
awarded  Nice Answer
Feb
7
answered The number of ways of selecting $n$ cards out of unlimited number of cards bearing the number $0,9,3$
Feb
6
revised Independence of a certain Linear combination of random variables
Made it more accurate to talk about independence in the title
Feb
6
comment limit ${\lim_{x \to 49} \frac{\sqrt{x}-7}{x-49} }.$
It's a stretch for most people to think of $x - 49$ as something that can be expressed in the form $a^2 - b^2$.
Feb
6
suggested approved edit on Independence of a certain Linear combination of random variables
Feb
6
comment limit ${\lim_{x \to 49} \frac{\sqrt{x}-7}{x-49} }.$
I don't think this helps to understand the problem in a way for the asker to apply in the future.
Feb
6
answered limit ${\lim_{x \to 49} \frac{\sqrt{x}-7}{x-49} }.$
Feb
6
answered Why, given a natural number $n$, does $n^6$ always have the remainder of 1 when divided by 7?
Jan
25
awarded  Critic
Jan
25
answered If there exists a function that maps A onto B , show that A is also uncountable
Jan
21
answered European Calls: arbitrage
Jan
21
awarded  Organizer
Jan
21
revised European Calls: arbitrage
It's a homework problem