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visits member for 1 year, 11 months
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Dec
13
comment Optimization of a function
The usual way is to analyze where the partial derivatives are zero. If there is no (visible) analytical solution, a numerical solution might be sufficient. Make sure that you don't get stuck in a local optimum. The numerical values sometimes help to discover the analytical solution not seen in the first place.
Dec
12
awarded  Revival
Dec
12
revised Write the following Boolean expression in product of sums form?
fixed a bug in last expression
Dec
11
answered Boolean algebra - cube - minimal disjunctive normal form
Dec
11
answered Write the following Boolean expression in product of sums form?
Dec
11
answered Boolean algebra: Minimizing a product of sums expression?
Dec
11
comment simply boolean expression into 4 literals
$A'B'$ is equivalent to $(A \lor B)'$. $A' \lor B'$ is equivalent to $(AB)'$.
Dec
11
answered Simplifying Boolean Function with Karnaugh Map
Dec
11
answered Simplying Boolean-Logic Expression
Dec
10
revised Just a proof of algebra
added 36 characters in body
Dec
10
answered Just a proof of algebra
Dec
9
comment How to decompose this polynomial?!
You could make use of $(x^{5k}+x^k+1) = (x^{2k}+x^k+1)(-x^{2k}+x^{3k}+1)$
Dec
8
awarded  Caucus
Dec
8
comment A circle and six sectors
The sum of the odd numbered sectors is 2. The sum of the even numbered sectors is 0. If all numbers are equal, the odd sum and the even sum have to be equal. How can this be achieved?
Dec
8
answered Optimization of a function
Dec
4
comment Circles intersecting at A and B
Do you assume that both circles are of the same size?
Dec
1
comment Solving unit vectors equations
For a unit vector $u$, product $u\cdot u$ is $1$. The same is true for $v\cdot v$. So, it remains to be shown that $u\cdot v - v\cdot u$ is in fact $0$.
Nov
24
comment Simplifying Boolean Function with Karnaugh Map
You can convince yourself that your expression is wrong. ABCD should be 1 but is not according to your result.
Nov
17
revised If one shows that UNIQUE k-SAT is in P, does it imply P=NP?
added reference links
Nov
17
suggested approved edit on If one shows that UNIQUE k-SAT is in P, does it imply P=NP?