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| bio | website | |
|---|---|---|
| location | Rome, Italy | |
| age | 22 | |
| visits | member for | 4 months |
| seen | 3 hours ago | |
| stats | profile views | 353 |
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9h |
comment |
Diagonalizability in $\mathbb{R}$ and $\mathbb{C}$ Try to look at a rotation matrix |
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10h |
asked | Cachazo-Douglas-Seiberg-Witten conjecture. |
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1d |
comment |
Proving that the cohomology ring of $\mathbb{R}P^n$ is isomorphic to $\mathbb{Z}_{2}[x]/(x)^{n+1}$ @SammyBlack But why $H^{n-2}$? and why $\mathbb{R}P^{n-1}$ isn't the $0-$class in homology? |
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1d |
comment |
Proving that the cohomology ring of $\mathbb{R}P^n$ is isomorphic to $\mathbb{Z}_{2}[x]/(x)^{n+1}$ @SammyBlack But how can I find the isomorphism? |
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1d |
asked | Proving that the cohomology ring of $\mathbb{R}P^n$ is isomorphic to $\mathbb{Z}_{2}[x]/(x)^{n+1}$ |
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2d |
comment |
Cohomology $H^ {i}(\mathbb{R}P^n, \mathbb{Z}_2)$ The functor $Hom=(-,\mathbb{Z}_2)$ what categories involves? |
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2d |
comment |
Cohomology $H^ {i}(\mathbb{R}P^n, \mathbb{Z}_2)$ I don't know why up the secondo arrow there is a $2$... are there all 0? |
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2d |
comment |
Cohomology $H^ {i}(\mathbb{R}P^n, \mathbb{Z}_2)$ @OlivierBégassat I wish to know only the group structure and I know only CW and singular cohomology... |
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2d |
comment |
Cohomology $H^ {i}(\mathbb{R}P^n, \mathbb{Z}_2)$ @ No.. I'm sorry |
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2d |
asked | Cohomology $H^ {i}(\mathbb{R}P^n, \mathbb{Z}_2)$ |
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May 15 |
comment |
Dolbeault cohomology of $S^{2n-1} \times S^1$ @Matt Yes, I posted also on MO but I don't understand why this form is closed but non exact... |
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May 15 |
comment |
Dolbeault cohomology of $S^{2n-1} \times S^1$ @Matt Yes... I wrote it. |
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May 15 |
asked | Dolbeault cohomology of $S^{2n-1} \times S^1$ |
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May 13 |
comment |
Isomorphism $\left(\mathbb{C}^{n}\setminus\{0\}\right)/\mathbb{Z}$ with $S^{1} \times S^{2n-1}$ How can I define $\equiv$? |
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May 13 |
asked | Isomorphism $\left(\mathbb{C}^{n}\setminus\{0\}\right)/\mathbb{Z}$ with $S^{1} \times S^{2n-1}$ |
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May 13 |
comment |
Tangent bundle of Grassmann manifold @KimJung-un It is very easy for $T\mathbb{R}P^n$, because we can define the application $$ T\mathbb{R}P^n \rightarrow Hom(\gamma^1, \gamma^\perp) $$ sending the line in $S^n$ passing for $x$ and $-x$ in the application $L:\gamma^1 \rightarrow \gamma^\perp$ sending the line $l_x$ in the vector $v \in L^\perp$ such that $<x,v>=0$. |
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May 12 |
asked | Tangent bundle of Grassmann manifold |
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May 11 |
comment |
$GL(n, \mathbb{C})$ is algebraically closed? @BenjaLim Let $n$ be a natural number. We can take $n$ elements in $GL$ and with them we can build a polinomial $p$ with $deg(p)=n−1$. Is it true that this polynomial has roots in $GL$? |
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May 11 |
comment |
$GL(n, \mathbb{C})$ is algebraically closed? @MichaelJoyce Let $n$ be a natural number. We can take $n$ elements in $GL$ and with them we can build a polinomial $p$ with $deg(p)=n-1$. Is it true that this polynomial has roots in GL? |
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May 11 |
answered | Proof of Volume of sphere |
