18,746 reputation
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bio website tancast.com/wp-content/…
location Where it's always Christmas
age
visits member for 4 years
seen 13 hours ago

May
7
asked Meaning of $( \alpha_i = ((0,\dots, a_n, \dots, 0)) $ converges in $\mathbb{R}^\infty$
May
5
comment Entangled circle in a solid torus (follow up)
@Aaron: thank you! Would you make that comment into an answer? Then I can accept it and this question is answered.
May
5
asked Entangled circle in a solid torus (follow up)
May
4
revised Why is this entangled circle not a retract of the solid torus?
added 42 characters in body
May
4
comment Why is this entangled circle not a retract of the solid torus?
Can someone tell me if I got it right? Ta!
May
4
answered Why is this entangled circle not a retract of the solid torus?
Apr
26
comment $\lim_{n\to \infty }\frac{a_{n+1}}{a_{n}}< 1$, $a_{_{n}}> 0$- does $a_{_{n}}$ converge?
@Jason: thank you for clarifying!
Apr
25
comment Follow up question about translation of a limit expression
@Didier: I think you are right, especially about behaviour generated by the rating system. For exactly this reason I don't down vote. I've undeleted my answer in the other thread.
Apr
25
revised $\lim_{n\to \infty }\frac{a_{n+1}}{a_{n}}< 1$, $a_{_{n}}> 0$- does $a_{_{n}}$ converge?
deleted 36 characters in body
Apr
25
comment Follow up question about translation of a limit expression
@Didier: yes, I know. I would've left it but I don't want to accumulate down votes : / I'm sorry, I would've kept the comments visible if it had been possible.
Apr
25
comment Fundamental Group of a finite set with discrete topology
@Theo: thank you, now I understand. I didn't understand why it was necessary to pick base points when one can show that every point in $S$ can only have the constant loop. It's necessary because that is how the fundamental group is defined.
Apr
25
comment Follow up question about translation of a limit expression
@david: true but neither does the first line.
Apr
25
asked Follow up question about translation of a limit expression
Apr
25
comment $\lim_{n\to \infty }\frac{a_{n+1}}{a_{n}}< 1$, $a_{_{n}}> 0$- does $a_{_{n}}$ converge?
@Didier: yes, I see the difference.
Apr
25
comment $\lim_{n\to \infty }\frac{a_{n+1}}{a_{n}}< 1$, $a_{_{n}}> 0$- does $a_{_{n}}$ converge?
@Didier: I think I'll have to make my own, follow up question about this "translation". I still don't see what's wrong.
Apr
25
comment $\lim_{n\to \infty }\frac{a_{n+1}}{a_{n}}< 1$, $a_{_{n}}> 0$- does $a_{_{n}}$ converge?
@Didier: Ah! Yes but Martin's comment writes that I'm proving that the limit is zero, which I'm not.
Apr
25
comment $\lim_{n\to \infty }\frac{a_{n+1}}{a_{n}}< 1$, $a_{_{n}}> 0$- does $a_{_{n}}$ converge?
@Nir: No. But as for now you should use david's answer, it seems there might be something wrong in the reasoning with my answer.
Apr
25
revised $\lim_{n\to \infty }\frac{a_{n+1}}{a_{n}}< 1$, $a_{_{n}}> 0$- does $a_{_{n}}$ converge?
Clarification added.
Apr
25
comment $\lim_{n\to \infty }\frac{a_{n+1}}{a_{n}}< 1$, $a_{_{n}}> 0$- does $a_{_{n}}$ converge?
@Didier: sorry, can you explain a bit more detailed, I can't find my mistake, even reading your comment above, thank you!
Apr
25
comment $\lim_{n\to \infty }\frac{a_{n+1}}{a_{n}}< 1$, $a_{_{n}}> 0$- does $a_{_{n}}$ converge?
@Didier, @Martin: I'm not proving that the limit is $0$!