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Jun
14
asked What does the $t$ in $(x,y,z)^t$ mean?
Jun
12
comment What to do with a hanging $1$ in a Karnaugh map?
@tpb261: Would it still be correct if I didn't group it with another $1$?
Jun
12
asked What to do with a hanging $1$ in a Karnaugh map?
Jun
7
asked What is a coordinate system?
Jun
5
comment 'Obvious' theorems that are actually false
@MJD: If you keep expanding the surface area of the clay, won't it reach a point in which the distance between the atoms is great enough causing the clay to disintegrate? If that was the case, you shouldn't be able to expand a clay's surface area infinitely (I dunno, I'm no mathematician).
Jun
2
accepted Creating groups with 10 men and 10 women.
Jun
2
comment Creating groups with 10 men and 10 women.
Thank you, I think the formula in the first one confuses me. What is the logic behind it exactly? (Yeah I just used the same formula in the third question without knowing why)
Jun
2
comment Creating groups with 10 men and 10 women.
@DanielY: Well, yeah, no reason in particular. I just used the permutations formula. I think it's the same thing?
Jun
2
asked Creating groups with 10 men and 10 women.
Jun
2
comment Creating digit sequences that can't begin with $0$, but one digit must repeat exactly once.
@RossMillikan: I see. So if the question meant that the two repeated digit must be together, I would apply Bananarama's answer?
Jun
2
asked Creating digit sequences that can't begin with $0$, but one digit must repeat exactly once.
Jun
2
accepted Creating teams with exactly two men and one woman, where the order matters.
Jun
2
asked Creating teams with exactly two men and one woman, where the order matters.
Jun
2
accepted Choosing two colours of different tones.
Jun
2
comment Choosing two colours of different tones.
@user3678068: No, it doesn't count.
Jun
1
asked Choosing two colours of different tones.
Jun
1
accepted Counting when there are two inclusive conditions.
Jun
1
comment Counting when there are two inclusive conditions.
@vadim123: Ah, so the answer would be like $$2^7 + 2^4$$ I think?
Jun
1
asked Counting when there are two inclusive conditions.
Jun
1
comment Checking when a player has all four aces from a deck distribution.
@HennoBrandsma: Yeah, you're right. I fixed it now, thanks.