Zol Tun Kul
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 8h awarded Popular Question Apr11 awarded Nice Question Feb6 awarded Popular Question Jan13 awarded Yearling Dec12 awarded Notable Question Oct25 comment Does the line $(2,1,1)+t(-3,1,5)$ live within the plane $31x+3y+18z=62$? @Galc127: The formula you posted, is that for calculating the orthogonal projection? In that case, don't I have to multiply the result by $(31,3,18)$, and then calculate the magnitude of the result? Oct24 accepted Does the line $(2,1,1)+t(-3,1,5)$ live within the plane $31x+3y+18z=62$? Oct24 asked Does the line $(2,1,1)+t(-3,1,5)$ live within the plane $31x+3y+18z=62$? Oct24 accepted The normal equation of the plane that contains the line $(1,1,1) + t(-2,0,3)$ Oct24 accepted Why isn't the orthogonal vector to a direction vector of a plane not necessarily perpendicular to such plane? Oct24 comment Why isn't the orthogonal vector to a direction vector of a plane not necessarily perpendicular to such plane? Would the same apply parallel vectors? I mean, if I find a vector that is parallel to that line's direction vector, would it also be parallel to the plane? Oct24 asked Why isn't the orthogonal vector to a direction vector of a plane not necessarily perpendicular to such plane? Oct24 asked The normal equation of the plane that contains the line $(1,1,1) + t(-2,0,3)$ Oct14 awarded Popular Question Oct3 accepted Deriving $\frac{8}{\sqrt{x-2}}$ Oct2 awarded Notable Question Oct2 asked Deriving $\frac{8}{\sqrt{x-2}}$ Oct1 comment Why $(-1 \cdot h) = -1$ when $h$ approaches $0$? By the way, if $h \not = 0$, how come the denominator is $(x-1)^2$? I had said that "$h$ is practically $0$" but I'm not that convinced anymore. Oct1 accepted Why $(-1 \cdot h) = -1$ when $h$ approaches $0$? Oct1 asked Why $(-1 \cdot h) = -1$ when $h$ approaches $0$?