meta user
network profile
| bio | website | |
|---|---|---|
| location | ||
| age | 18 | |
| visits | member for | 2 years, 4 months |
| seen | May 7 at 0:55 | |
| stats | profile views | 102 |
'ello fellas!
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Jul 5 |
comment |
Simplifying to a certain expression structure With the AC-method, I'm still not sure how would I reach $$4(n+1)^2-(n+1)$$ |
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Jul 5 |
asked | Simplifying to a certain expression structure |
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Jul 4 |
comment |
How to get the characteristic equation? It.... IT WORKS. Awesome, thank you!!! |
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Jul 4 |
accepted | How to get the characteristic equation? |
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Jul 4 |
asked | How to get the characteristic equation? |
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Jul 3 |
comment |
Simplifying to a desired expression structure I'm enlightened. Thank you. |
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Jul 3 |
accepted | Simplifying to a desired expression structure |
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Jul 3 |
comment |
Simplifying to a desired expression structure Ah! I... didn't see that. Somehow. I'm eager to see how to extract such though. |
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Jul 3 |
asked | Simplifying to a desired expression structure |
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Jul 1 |
comment |
How to prove if a function is bijective? You know, it had me thinking: according to your method to find out if it is injective, no matter what function I test it with, I always manage to get the final equality (x = y). How would a function ever be not-injective? |
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Jul 1 |
accepted | How to prove if a function is bijective? |
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Jul 1 |
comment |
How to prove if a function is bijective? "Subtract 3 and divide by 2, again we have (y−3)/2=f(x). As before, if f was surjective then we are about done" I'm not sure, but why would we be done there? |
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Jul 1 |
awarded | Yearling |
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Jul 1 |
comment |
How to prove if a function is bijective? Sorry, yes, f is bijective. Thank you for clarifying that :) |
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Jul 1 |
revised |
How to prove if a function is bijective? deleted 3 characters in body |
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Jul 1 |
awarded | Editor |
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Jul 1 |
revised |
How to prove if a function is bijective? added 64 characters in body |
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Jul 1 |
comment |
How to prove if a function is bijective? My apologies! Yes, f is a bijection. |
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Jul 1 |
asked | How to prove if a function is bijective? |
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Mar 20 |
awarded | Commentator |
